Clues by Sam May 10, 2026 Answer – Full Solution Explained
A1
😬
princess
B1
👨💻
coder
C1
👨⚕️
doctor
D1
👩💻
coder
A2
💂♀️
guard
B2
😬
bear
C2
😬
bear
D2
😬
bear
A3
👩🔧
mech
B3
👩✈️
pilot
C3
👩🌾
farmer
D3
🕵️♀️
sleuth
A4
👩🔧
mech
B4
👩✈️
pilot
C4
💂♂️
guard
D4
👨🌾
farmer
A5
👩🔧
mech
B5
👮♀️
cop
C5
👮♂️
cop
D5
👮♀️
cop
Final Board State
This puzzle is fully solved.
All characters have been identified as innocent or criminal based on today's clues.
See how each clue leads to the final result
Skip the reasoning — 4 criminals.
Clues by Sam answer for May 10, 2026 — a Hard solved in 14 steps
Today's Clues by Sam puzzle is rated Hard and resolves with 4 criminals on a 20-cell, 4-column × 5-row grid. The criminals are Luigi (D2), Wanda (B5), Xavi (C5) and Zoe (D5); the remaining 16 suspects are innocent.
The deduction chain, in plain English
01.A4 · Rose → INNOCENT, A2 · Frida → INNOCENT
Umar’s clue says exactly 2 innocents are in the overlap between the people below Ariel and Mary’s neighbors. That shared group is only Frida and Rose. Since the clue still needs 2 innocents in that group, and Frida and Rose are the only people there, both of them have to fill those two innocent spots. So Rose and Frida must be innocent.
02.C5 · Xavi → CRIMINAL, D5 · Zoe → CRIMINAL
Frida's clue says exactly 2 cops have a criminal directly to the right of them. Those 2 cases still have to come from the cop group, and the only people left whose direct-right relationship still matters for this clue are Xavi and Zoe. Since both remaining cases must be supplied there, Xavi and Zoe must be criminal.
03.B3 · Olive → INNOCENT
Zoe's clue directly says that Olive is one of Kyle's seven innocent neighbors. Since Olive is explicitly included in that innocent group, Olive at B3 must be innocent.
04.C1 · Clyde → INNOCENT
Zoe’s clue says Kyle has exactly 7 innocent neighbors, and Kyle has 8 neighbors total with Olive already known innocent, so among Kyle’s other seven neighbors there is exactly 1 criminal. Rose’s clue limits that one criminal in row 2 to Barnie, Donna, Igor, Luigi, Paula, or Quita, not Clyde. That means Clyde cannot be the criminal among Kyle’s neighbors, so Clyde must be innocent.
05.A3 · Mary → INNOCENT
06.D3 · Quita → INNOCENT
Zoe says Olive is one of Kyle's 7 innocent neighbors, so among Kyle's 8 neighbors there is exactly 1 criminal. In that neighbor group, the only possible criminal is among Barnie, Donna, Igor, Luigi, and Paula. That leaves Quita unable to be the one criminal in Kyle's neighborhood, so Quita must be innocent.
07.C3 · Paula → INNOCENT
Zoe says Olive is one of Kyle's 7 innocent neighbors. Kyle has 8 neighbors total, and 3 of them are already known innocents, so among the 5 unknown neighbors there can be only 1 criminal. In row 2, Rose's clue says only one criminal has an innocent directly above, and the only row 2 people who are also Kyle's neighbors are Igor and Luigi. That means the single criminal among Kyle's unknown neighbors must be one of Barnie, Donna, Igor, or Luigi, not Paula. So Paula must be innocent.
08.D1 · Donna → INNOCENT
Kyle has exactly 7 innocent neighbors, and 4 of his neighbors are already known to be innocent, so among B1 Barnie, D1 Donna, B2 Igor, and D2 Luigi there is exactly 1 criminal. The one criminal in that group has to come from B1 Barnie, B2 Igor, or D2 Luigi, not from Donna. So D1 Donna must be innocent.
09.A1 · Ariel → INNOCENT
Among edge cells, there must be exactly 4 criminals, and only 1 of those edge criminals is in column B. Since Xavi and Zoe are already edge criminals and neither is in column B, the non-column-B edge positions still need exactly 1 more criminal, and in this step that remaining non-column-B edge choice is narrowed to Luigi or Vicky. That means Ariel is not that criminal. So Ariel must be innocent.
10.B1 · Barnie → INNOCENT, C2 · Kyle → INNOCENT
Kyle’s clue says Olive is one of Kyle’s exactly 7 innocent neighbors. Among Kyle’s neighbors, Clyde, Donna, Olive, Paula, and Quita are already innocent, so if Barnie were criminal and Kyle were criminal, then the remaining neighbor spots and the row counts would have to fit that 7-innocent requirement together with the rule that exactly one row has exactly one criminal. But with Barnie criminal and Kyle criminal, the people still involved here are Igor, Luigi, Stella, Tyler, Vicky, and Wanda, and those clues cannot all be satisfied at once. That means Barnie and Kyle cannot be criminal. So Barnie and Kyle must be innocent.
11.B5 · Wanda → CRIMINAL
Paula's clue says there are exactly 4 criminals on the edge, and exactly 1 of those edge criminals is in column B. Among the edge people in column B, Barnie is innocent and Wanda is the only person there not yet identified. So the one edge criminal in column B has to be Wanda. That makes Wanda criminal.
12.B4 · Stella → INNOCENT, C4 · Tyler → INNOCENT, A5 · Vicky → INNOCENT
Barnie’s clue says exactly 3 innocents in row 4 have a criminal directly below them. In row 4, the known innocents are Rose and Umar, while Stella and Tyler are the only other people there. If Stella, Tyler, and Vicky were all criminals, then the remaining people would have to satisfy that row 4 clue at the same time, and they cannot. That opposite assignment clashes with the requirement that exactly 3 innocents in row 4 have a criminal directly below them. So Stella, Tyler, and Vicky must be innocent.
13.D2 · Luigi → CRIMINAL
Paula's clue says there are exactly 4 criminals on the edge, and exactly 1 of those edge criminals is in column B. Since that 1 is already Wanda, the edge people not in column B must contain exactly 3 criminals. Among those edge people not in column B, Xavi and Zoe are already known criminals, so one more criminal is still needed there. The only unknown person left in that group is Luigi, so Luigi must be criminal.
14.B2 · Igor → INNOCENT
Zoe says Olive is one of Kyle's exactly 7 innocent neighbors. Among Kyle's neighbors, Barnie, Clyde, Donna, Olive, Paula, and Quita are already innocent, Luigi is criminal, and only Igor is still unknown. If Igor were criminal, Kyle's neighbors would have only 6 innocents, not the 7 the clue requires. So Igor must be innocent.