Clues by Sam Jun 08, 2026 Answer – Full Solution Explained

01.C1 · Debra → INNOCENT, C2 · Helen → INNOCENT

Eve's clue says exactly 2 people who are both in column C and neighboring Cheryl are innocent. That shared group contains only Debra and Helen. Since those 2 innocent spots in the group are still unfilled, and Debra and Helen are the only people there who can fill them, both of them have to be innocent. So Debra and Helen must be innocent.

02.D4 · Quita → CRIMINAL

03.C3 · Logan → CRIMINAL, A2 · Franco → CRIMINAL

Quita’s clue says exactly 2 of the 3 pilots have a criminal directly below them. Two such cases are still needed for that clue, and the only direct-below people that can still supply them are Franco below Barnie and Logan below Helen. Since those are the only two people left who can make the clue true, both of them have to be criminals. So Logan and Franco must be criminal.

04.D3 · Martin → CRIMINAL, D2 · Ivan → CRIMINAL

Franco’s clue says there is exactly one innocent above Quita. Above Quita, there is already one known innocent there: Eve. The only other people above Quita whose identities were not yet known are Ivan and Martin, so the one allowed innocent in that group is already accounted for and neither of them can be innocent. So Martin and Ivan must be criminal.

05.D5 · Xola → CRIMINAL

Ivan's clue says column D has exactly one innocent. Column D already has that one innocent, Eve. The only person in column D whose identity was still unknown is Xola, so Xola cannot also be innocent. So Xola must be criminal.

06.C5 · Vince → INNOCENT

Xola's clue means the cop profession contains exactly 1 innocent person. Right now there are 0 known innocents among the cops, and the only cop whose identity is still unknown is Vince. So the one innocent cop has to be Vince. That makes Vince innocent.

07.B2 · Gabe → CRIMINAL

Vince's clue says that the people to the right of Franco contain exactly 2 criminals. In that group, Ivan is already a known criminal, Helen is innocent, and the only person there not yet identified is Gabe. Since that group has 1 known criminal and still needs exactly 1 more criminal, the only remaining spot for that second criminal is Gabe. So Gabe must be criminal.

08.B3 · Karen → INNOCENT

09.A4 · Nick → INNOCENT

10.A3 · Jane → INNOCENT

11.C4 · Pip → CRIMINAL

Jane's clue says each column has at least 2 criminals, so column C can have at most 3 innocents. In column C, Debra, Helen, and Vince are already known innocents, which uses up all 3 innocent spots that column can have. That means the remaining person in column C, Pip, cannot be innocent. So Pip must be criminal.

12.B4 · Oscar → INNOCENT

13.A5 · Sofia → CRIMINAL, B5 · Uma → CRIMINAL

Oscar’s clue says there are exactly 2 criminals in row 5 who have an innocent directly above them. In row 5, Xola is already a known criminal, while Sofia and Uma are the only people there not yet identified. If Sofia and Uma were both innocent, then row 5 would not be able to satisfy Oscar’s requirement for exactly 2 such criminals. So Sofia and Uma must be criminal.

14.B1 · Cheryl → INNOCENT

Uma’s clue says columns B and C must have the same number of innocents. Column C already has 3 innocents, while column B currently has only 2 known innocents. If Cheryl were criminal, column B would stay at 2 innocents, so it could not match column C’s 3. So Cheryl must be innocent.

15.A1 · Barnie → CRIMINAL

Debra's clue says there are exactly 11 criminals in the whole board. Right now 10 people are already identified as criminals, and Barnie is the only person not yet identified. If Barnie were innocent, the total would stay at 10, which conflicts with Debra's clue. So Barnie must be criminal.