Clues by Sam Jun 29, 2026 Answer – Full Solution Explained
A1
🕵️♂️
sleuth
B1
👷♀️
builder
C1
👨🏫
teacher
D1
👩🏫
teacher
A2
👨🎤
singer
B2
👨🍳
cook
C2
👨🏫
teacher
D2
👩🎤
singer
A3
👨🎨
painter
B3
👩🍳
cook
C3
👨🎨
painter
D3
🕵️♀️
sleuth
A4
👷♂️
builder
B4
💂♀️
guard
C4
🕵️♀️
sleuth
D4
👮♀️
cop
A5
💂♂️
guard
B5
👮♀️
cop
C5
👨🎨
painter
D5
👮♀️
cop
Final Board State
This puzzle is fully solved.
All characters have been identified as innocent or criminal based on today's clues.
See how each clue leads to the final result
Skip the reasoning — 8 criminals.
Clues by Sam answer for Jun 29, 2026 — a Easy solved in 16 steps
Today's Clues by Sam puzzle is rated Easy and resolves with 8 criminals on a 20-cell, 4-column × 5-row grid. The criminals are Adam (A1), Bonnie (B1), Laura (B3), Paul (A4), Quita (B4), Umar (A5), Wally (C5) and Xena (D5); the remaining 12 suspects are innocent.
The deduction chain, in plain English
01.B2 · Floyd → INNOCENT
Chris’s clue says Floyd is one of the exactly 2 innocents in column B. Since Floyd is named as one of those innocents, his identity is given directly by the clue. So Floyd must be innocent.
02.C5 · Wally → CRIMINAL
Floyd’s clue says there are exactly 2 criminals to the left of Xena, and exactly 1 of those criminals is in column C. Among the people to the left of Xena, the only person who is also in column C is Wally at C5. So the 1 criminal in that column-C part has to be Wally. That makes Wally criminal.
03.B1 · Bonnie → CRIMINAL
Below Bonnie there are exactly 2 innocents, and those people are all in column B as well. Column B also has exactly 2 innocents total, with Floyd already one of them. Since the people below Bonnie account for all the innocents column B is allowed to have, the only person in column B who is not below Bonnie cannot be innocent. So Bonnie must be criminal.
04.A1 · Adam → CRIMINAL, D1 · Diane → INNOCENT
Bonnie’s clue says the two innocents in row 1 must be connected. In row 1, Chris is already known to be innocent and Bonnie is already known to be criminal, so the only question is whether Adam or Diane is the second innocent. If Adam were innocent while Diane were criminal, then the two innocents in that row would be Adam and Chris, and that does not fit the clue’s requirement that the two innocents be connected. So Adam must be criminal, and Diane must be innocent.
05.D5 · Xena → CRIMINAL
Row 5 has exactly one innocent, and there are currently no known innocents in that row, so row 5 needs exactly one innocent in total. Among the people to the left of Xena in row 5, Umar and Vera account for exactly one innocent. Xena is also in row 5, but not in that exact-count group. So Xena cannot also be innocent, and Xena at D5 must be criminal.
06.B4 · Quita → CRIMINAL
Xena’s clue says there are no innocents in the group that is both in row 4 and neighboring Paul. That shared group contains only Quita, and it already has 0 known innocents. So the only person left in that group cannot be innocent. That makes Quita criminal.
07.D3 · Olga → INNOCENT, D4 · Sofia → INNOCENT
Quita’s clue says the people strictly between Hazel and Xena contain exactly 2 innocents. That group currently has no known innocents, and the only people left in it are Olga and Sofia. Since the group still needs exactly 2 innocents and there are exactly 2 people available to fill those spots, both of them have to be innocents. So Olga and Sofia must be innocent.
08.A4 · Paul → CRIMINAL
Olga’s clue says exactly one corner person has a criminal directly above them. There must be one more such case beyond the ones already known, and the only direct-above person still affecting that clue is Paul at A4. So Paul has to be the criminal that makes that one required case. That makes Paul criminal.
09.C4 · Ruth → INNOCENT
Adam’s clue says row 5 is the only row with exactly one innocent. Row 4 already has one known innocent, and Ruth is the only person in that row not yet identified. If Ruth were criminal, then row 4 would remain at exactly one innocent, which the clue forbids for every row except row 5. So Ruth must be innocent.
10.D2 · Hazel → INNOCENT
Ruth’s clue says there is exactly 1 innocent among the people who are both in column D and neighboring Diane. That shared group is just Hazel at D2. There are currently 0 known innocents in that group, so the 1 innocent required by the clue has to be Hazel. So Hazel must be innocent.
11.C3 · Noah → INNOCENT, C2 · Ghani → INNOCENT
12.A2 · Eric → INNOCENT
Noah’s clue says row 3 is the only row with exactly one criminal. In row 2, there are currently no known criminals, and Eric is the only person there whose identity is not yet fixed. If Eric were a criminal, then row 2 would end up with exactly one criminal too, which would contradict the clue. So Eric must be innocent.
13.B5 · Vera → INNOCENT
Eric’s clue says exactly one corner person has a criminal directly to the right. That one case is already A1 Adam, since Bonnie to Adam’s right is a criminal. The only other corner case that could still change this clue is A5 Umar, because the person directly to Umar’s right is Vera. If Vera were criminal, then Umar would also count, making more than one such corner case. So Vera must be innocent.
14.A5 · Umar → CRIMINAL
Adam’s clue says row 5 is the only row with exactly one innocent. In row 5, Vera is already the one known innocent, with Wally and Xena already criminal, so Umar is the only person there who could change that row’s innocent count. If Umar were innocent, then row 5 would no longer have exactly one innocent, which clashes with Adam’s clue that row 5 is the only row with exactly one innocent. So Umar cannot be innocent. So Umar must be criminal.
15.B3 · Laura → CRIMINAL
Chris says Floyd is one of exactly 2 innocents in column B. In column B, the innocents are already Floyd and Vera. If Laura were also innocent, column B would have 3 innocents, which conflicts with that clue. So Laura must be criminal.
16.A3 · Jason → INNOCENT
Noah’s clue says row 3 is the only row with exactly one criminal. In row 3, Laura is already the one known criminal, and Jason is the only person there whose identity was still undecided. If Jason were criminal too, then row 3 would no longer have exactly one criminal, which clashes with Noah’s clue. So Jason at A3 must be innocent.