Clues by Sam Oct 12, 2026 Answer – Full Solution Explained

01.B4 · Rocio → CRIMINAL

Noah’s clue says the people strictly between Habi and Will contain exactly one innocent. That group already has one known innocent, Noah. The only other person left in that between-group is Rocio, so Rocio cannot also be innocent. So Rocio must be criminal.

02.D3 · Pip → CRIMINAL

Rocio's clue says row 3 has exactly 2 criminals, and exactly 1 of those criminals is Noah's neighbor. Since Noah's row-3 neighbors are Lujan and Olive, that means the other row-3 criminal must be in the row-3 people who are not Noah's neighbors. Those are Noah and Pip, but Noah is already innocent, so the only person left to fill that criminal spot is Pip. So Pip must be criminal.

03.B5 · Will → CRIMINAL, B2 · Habi → INNOCENT

Pip’s clue says there are exactly two innocents below Bianca, and those two innocents must be connected. Below Bianca are Habi, Noah, Rocio, and Will, with Noah already innocent and Rocio already criminal. If Will were innocent and Habi were criminal, then the two innocents below Bianca would be Noah and Will, but that does not fit the clue’s requirement for the two innocents below Bianca. So Will must be criminal and Habi must be innocent.

04.C5 · Xena → INNOCENT

The clue says there is exactly one innocent in the overlap between the people to the right of Vera and Rocio's neighbors. That shared group is just Will and Xena. Will is already a criminal, so the shared group currently has no known innocent. Since Xena is the only unknown person left in that group, she has to be the one innocent required by the clue. So Xena must be innocent.

05.B1 · Bianca → INNOCENT

Xena’s clue says column C is the only column with exactly 3 criminals. In column B, Rocio and Will are already criminals, and Bianca is the only person there not yet identified. If Bianca were a criminal too, then column B would also have exactly 3 criminals, which the clue forbids. So Bianca must be innocent.

06.C4 · Tina → CRIMINAL

Bianca’s clue says an odd number of the people who are both above Xena and neighbors of Habi are innocent. That shared group is exactly Claudio, Igor, and Olive. If Tina were innocent, then Xena’s clue that column C has exactly 3 criminals would make the three criminals in column C be Claudio, Igor, and Olive, so Claudio, Igor, and Olive would all be criminal. But then in that shared group of Claudio, Igor, and Olive, the number of innocents would be 0, which is not odd. So Tina must be criminal.

07.D4 · Umar → INNOCENT

Tina’s clue says the people to the right of Rocio contain exactly one innocent. In that group, there are currently no known innocents, and the only unknown person left there is Umar. So the one innocent required by the clue has to be Umar. That makes Umar innocent.

08.D1 · Emilia → CRIMINAL

Umar’s clue says Klay’s neighbors contain an odd number of innocents. Right now that neighbor group has no known innocents, and the unknown neighbors are Claudio, Emilia, Igor, and Olive. If Emilia were innocent, those people would also have to fit Xena’s clue that column C is the only column with exactly 3 criminals, together with Umar’s odd-innocents requirement around Klay, and that combination is impossible. So Emilia cannot be innocent. That makes Emilia criminal.

09.A4 · Quita → CRIMINAL

If Quita were innocent, then row 4 would already have 2 innocents, Quita and Umar. Emilia’s clue says row 3 has more innocents than row 4, so row 3 would need more than 2 innocents. Row 3 already has Noah as an innocent, and row 3 has exactly 2 criminals total. That means the only two unknown people in row 3, Lujan and Olive, would both have to be innocent to push row 3 up to 3 innocents. But Rocio’s clue says that of the 2 criminals in row 3, exactly 1 is Noah’s neighbor, and the two row 3 neighbors of Noah are Lujan and Olive. If both Lujan and Olive were innocent, that condition could not be met. So Quita must be criminal.

10.C2 · Igor → CRIMINAL

The clue says exactly 2 of the 3 cops have an innocent directly to the left. Igor has Habi, who is innocent, directly to his left, and Olive has Noah, who is innocent, directly to her left, so those two already make up the full count of 2. Klay has Igor directly to his left, so if Igor were innocent, Klay would also be a cop with an innocent directly to the left, making 3 instead of 2. So Igor must be criminal.

11.A2 · Ghani → CRIMINAL

12.A1 · Augustin → CRIMINAL

Ghani’s clue explicitly says that Augustin is a criminal. That directly fixes Augustin’s identity without needing any other clue or board relationship. So Augustin must be criminal.

13.D5 · Zulu → INNOCENT

Among the singers, exactly one person can have a criminal directly to the right. That one case is already provided by Vera. The only other singer whose identity could still change this clue is Zulu, and if Zulu were criminal then the clue would have more than that one counted case. So Zulu must be innocent.

14.D2 · Klay → INNOCENT

Xena’s clue says column C is the only column that has exactly 3 criminals. In column D, there are already 2 known criminals, and Klay is the only person in that column not yet identified. If Klay were criminal, then column D would also have exactly 3 criminals, which is not allowed. So Klay must be innocent.

15.C1 · Claudio → INNOCENT

Zulu says only one row has exactly 3 criminals. Row 4 already fits that exactly, with Quita, Rocio, and Tina as criminals and Umar as innocent. Row 1 already has 2 known criminals, and Claudio is the only person there not yet identified, so if Claudio were a criminal then row 1 would also have exactly 3 criminals. That would clash with Zulu's clue, so Claudio at C1 must be innocent.

16.C3 · Olive → CRIMINAL

Xena’s clue says column C is the only column with exactly 3 criminals. In column C, Igor and Tina are already criminals, while Claudio and Xena are innocents, so the only undecided person in that column is Olive. To make column C have exactly 3 criminals, Olive has to be the third criminal. So Olive must be criminal.

17.A3 · Lujan → INNOCENT

Row 3 has exactly 2 criminals in total. The clue also says exactly 1 of the row 3 criminals is Noah's neighbor, and among the row 3 people who are Noah's neighbors, Olive is already a known criminal. Since that one neighboring criminal is already accounted for by Olive, the only other row 3 neighbor of Noah, Lujan, cannot be a criminal. So Lujan must be innocent.

18.A5 · Vera → CRIMINAL

Xena’s clue says column C is the only column with exactly 3 criminals. Column A already has 3 known criminals, and Vera is the only person in that column not yet identified. If Vera were innocent, then column A would also have exactly 3 criminals, which the clue does not allow. So Vera must be criminal.