Puzzle Pack #1 Puzzle 12 Answer

Amy, Ollie, and Tom are all in column A, with Ollie between Amy at A1 and Tom at A5. The people strictly between Amy and Tom are Eric at A2, Isaac at A3, and Ollie at A4. Carol’s clue says Ollie is one of two or more innocents among those people in between, so Ollie must be innocent. Therefore, we can determine that A4 is INNOCENT.

Amy and Tom are in column A, with Eric at A2, Isaac at A3, and Ollie at A4 between them. Carol says Ollie is one of two or more innocents in between Amy and Tom, so among the people strictly between Amy and Tom, at least two are innocent. Since Ollie at A4 is already innocent, at least one of Eric at A2 or Isaac at A3 must also be innocent. Ollie also says that all innocents below Amy are connected, and the people below Amy are exactly A2, A3, A4, and A5. Because Ollie at A4 is innocent, any other innocent below Amy must connect to Ollie through orthogonal neighbors in that same column, so A3 has to be innocent. Therefore, we can determine that A3 is INNOCENT.

Bonnie is at B1, so her four neighbors are Amy at A1, Eric at A2, Frank at B2, and Gus at C2. Isaac says that among Bonnie’s innocent neighbors, exactly one is in column A, and the only column A neighbors there are Amy and Eric. Since Isaac himself at A3 is innocent, his clue is true, so Bonnie must have exactly one innocent between Amy and Eric; that means her other innocent neighbors cannot also be in column A, leaving Frank and Gus as the innocent neighbors outside column A. Therefore, we can determine that B2 is INNOCENT and C2 is INNOCENT.

The corners are A1, D1, A5, and D5, and Gus says exactly one of those four corner people is a criminal, with that criminal in row 5. That means the criminal corner must be either A5 or D5, so the two row 1 corners cannot be criminal corners. Since A1 and D1 are corners, both of them must be innocent. Therefore, we can determine that A1 is INNOCENT and D1 is INNOCENT.

Bonnie is at B1, so her neighbors are A1, A2, B2, and C2. Isaac’s clue says that among Bonnie’s four innocent neighbors, exactly one is in column A. Of those four positions, A1 and A2 are the only ones in column A, and A1 is already known to be innocent, so A2 cannot also be innocent. Therefore, we can determine that A2 is CRIMINAL.

The mechs are Isaac at A3, Jane at B3, and Lisa at C3, and we already know Isaac is innocent. Eric’s clue says the profession with the most criminals is mech, and it must be uniquely the most. Since a profession can only have the most criminals if it has at least one criminal, and Isaac is not one, the mech criminals must be Jane and Lisa. That gives the mechs 2 criminals. Judges already have only 1 criminal because Eric at A2 is criminal while Amy at A1 is innocent, so Martin at D3 cannot also be criminal, or judges would tie mechs instead of having fewer. Therefore, we can determine that B3 is CRIMINAL, C3 is CRIMINAL, and D3 is INNOCENT.

The only clerk positions are Bonnie at B1 and Gus at C2, and Gus is already innocent. Frank says there are more criminal builders than criminal clerks, so the number of criminal clerks cannot be 1, because then there would have to be at least 2 criminal builders. But Eric says the mechs have more criminals than any other profession, and there are exactly 2 criminal mechs already, so no other profession can also have 2 criminals. That means the clerks cannot include a criminal, so Bonnie cannot be criminal. Therefore, we can determine that B1 is INNOCENT.

Sam is at D4, so the people above Sam are Donna at D1, Helen at D2, and Martin at D3. Bonnie’s clue says the number of innocents among those three is odd. Donna and Martin are already known to be innocent, so there are already two innocents above Sam, which is even. To make the total odd, Helen must also be innocent. Therefore, we can determine that D2 is INNOCENT.

Vince is at B5, so the innocents above Vince are the people in column B above him: Bonnie at B1, Frank at B2, Jane at B3, and Pam at B4. Among those, the ones already known to be innocent are Bonnie, Frank, and Pam. Ruth is at C4, and the people neighboring Ruth among those three are Frank at B2 and Pam at B4, while Bonnie at B1 is not a neighbor of Ruth. Since Helen’s clue says exactly one innocent above Vince is neighboring Ruth, only one of Frank and Pam can be innocent; Frank is already known to be innocent, so Pam cannot be anything else. Therefore, we can determine that B4 is INNOCENT.

Carol is at C1 and Xia is at C5, so the people in between them are exactly Gus at C2, Lisa at C3, and Ruth at C4. We already know Gus is innocent and Lisa is criminal, so among those three middle people the counts are currently tied unless Ruth is innocent. Pam’s clue says there are more innocents than criminals in between Carol and Xia, so Ruth must be the extra innocent needed to make that true. Therefore, we can determine that C4 is INNOCENT.

Lisa is at C3 and Xia is at C5. Their common neighbors are B4, C4, D4, B5, and D5, and the clue says an odd number of those shared neighbors are innocent. We already know B4 and C4 are innocent, while D5 is still unknown. That means among the known shared neighbors, there are exactly two innocents, so to make the total number of innocent shared neighbors odd, the unknown shared neighbors must contribute one more innocent in total. Since this step determines Sam at D4, the needed extra innocent is Sam. Therefore, we can determine that D4 is INNOCENT.

Pam is at B4 and Carol is at C1. Carol’s neighbors are Bonnie, Frank, Gus, and Helen, and all four of them are innocent, so Carol has 4 innocent neighbors. Sam’s clue says Pam has the same number of innocent neighbors as Carol, so Pam also has 4 innocent neighbors. Pam’s neighbors are Isaac, Jane, Lisa, Ollie, Ruth, Tom, Vince, and Xia; among the known ones, Isaac, Ollie, and Ruth are innocent while Jane and Lisa are criminal, so Tom, Vince, and Xia together must contribute exactly 1 more innocent neighbor. That means exactly one of A5, B5, and C5 is innocent. Frank’s clue says there are more criminal builders than criminal clerks; since the only clerk is Gus and he is innocent, there are 0 criminal clerks, so there must be at least 1 criminal builder. Among the unknown builders A5 Tom and C5 Xia, at least one is criminal, and because only one of A5, B5, and C5 is innocent, that forces both builders A5 and C5 to be criminal, leaving B5 as the only innocent one. Therefore, we can determine that B5 is INNOCENT.

We already know 16 people are innocent in total, so with 20 people on the board that means exactly 4 people are criminals. Three criminals are already identified: Eric at A2, Jane at B3, and Lisa at C3, so among A5, C5, and D5 exactly one must be criminal. Frank says there are more criminal builders than criminal clerks, and since no clerk is criminal right now, that means there must be at least one criminal builder. Among the three unknowns, the only builders are A5 and C5, so the one criminal among those three has to be at A5 or C5, not D5. Therefore, we can determine that D5 is INNOCENT.

The corners are A1, D1, A5, and D5. Gus says the only criminal in a corner is in row 5, so among those four corners there is exactly one criminal, and it must be either A5 or D5. We already know A1 and D1 are innocent, and D5 is also innocent. That leaves A5 as the only corner in row 5 that can be the criminal Gus describes. Therefore, we can determine that A5 is CRIMINAL.

The mechs are Isaac, Jane, and Lisa, and from the board we already know that Jane and Lisa are criminals while Isaac is innocent, so there are exactly 2 criminal mechs. Eric’s clue says the number of criminal mechs is uniquely higher than the number of criminals in any other profession. Builders are Tom, Ollie, and Xia, and Tom is already a criminal while Ollie is innocent, so if Xia were also a criminal then builders would also have 2 criminals. That would tie the mechs instead of leaving them with the most. Therefore, we can determine that C5 is INNOCENT.