Puzzle Pack #1 Puzzle 20 Answer

Eve is at A2, so everyone to her right in the same row is B2, C2, and D2: Floyd, Gus, and Isaac. Paula’s clue says Floyd is one of the 2 innocents to the right of Eve, which directly includes Floyd among those two innocents. Therefore, we can determine that Floyd is INNOCENT.

Row 4 contains Paula at A4, Ruby at B4, Sofia at C4, and Thor at D4, and Floyd says there are exactly two criminals in that row and they must be connected. Since Paula at A4 is already known to be innocent, the only way to place two connected criminals in row 4 is for them to be at C4 and D4. That forces Sofia to be one of those two criminals. Therefore, we can determine that C4 is CRIMINAL.

Paula says Floyd is one of the two innocents to the right of Eve. Since Floyd is at B2, Eve must be in the same row to his left, so Eve is at A2, and the only people to Eve’s right in row 2 are B2, C2, and D2. Paula’s clue means exactly two of those three are innocent, and one of them is Floyd. Sofia says row 2 contains an odd number of innocents. Paula at A4 is already known innocent, and everyone tells the truth, so Sofia’s clue is true even though Sofia is a criminal. If Eve were criminal, then row 2 would have innocents only among B2, C2, and D2, and Paula’s clue says there are exactly two there, which is even, not odd. So Eve must be the extra innocent that makes the total in row 2 odd. Therefore, we can determine that A2 is INNOCENT.

The two innocents in column C must both be next to Isaac at D2. Isaac’s neighbors are C1, C2, C3, D1, and D3, so in column C the only neighbors he has are C1, C2, and C3. That means the two innocents in column C are among C1, C2, and C3, so the other two people in column C, C4 and C5, cannot be innocent. Since C4 is already known to be criminal, C5 must be criminal as well. Therefore, we can determine that C5 is CRIMINAL.

Paula is at A4, so her neighbors are only Katie at A3, Ruby at B4, and Vicky at A5. Nobody in row 5 is adjacent to Paula except Vicky at A5. Xavi says there are 3 criminals in row 5, and only 1 of them is Paula's neighbor, so that one must be Vicky and the other two people in row 5 besides Xavi cannot be Paula's neighbors. Since Xavi at C5 is already a criminal, the remaining criminal in row 5 must be Zed at D5, not Wanda at B5. Therefore, we can determine that D5 is CRIMINAL.

Eve is at A2, so her neighbors are A1, B1, B2, A3, and B3. The clue says the only innocent pilot is one of Eve’s neighbors, so any pilot who is not in that neighbor set cannot be innocent. Olivia at D3 is a pilot, and D3 is not a neighbor of Eve. Therefore, we can determine that D3 is CRIMINAL.

Olivia’s clue says that Bruce is a criminal, and also that row 1 contains at least one other criminal besides him. Since the clue directly states Bruce’s identity, nothing else is needed here. Therefore, we can determine that B1 is CRIMINAL.

In column D, we already know that D3 and D5 are criminals. The clue says that all criminals in column D are connected, and in a single column that means they must form one continuous vertical block with no innocent person between them. The only person between D3 and D5 is D4, so D4 has to be a criminal to keep those criminals connected. Therefore, we can determine that D4 is CRIMINAL.

In row 4, the two criminals are already Sofia at C4 and Thor at D4. Floyd’s clue says both criminals in that row are connected, which means every criminal in row 4 must form one continuous left-right group with no innocent between them. Since C4 and D4 are adjacent, that connected criminal group is already complete, so B4 cannot also be a criminal. Therefore, we can determine that B4 is INNOCENT.

Gus is at C2 and Xavi is at C5, so the people in between them are Martin at C3 and Sofia at C4. Ruby’s clue says there is only one innocent in between Gus and Xavi, meaning exactly one of those two people is innocent. Since Sofia at C4 is already known to be criminal, the only possible innocent between Gus and Xavi is Martin at C3. Therefore, we can determine that C3 Martin is INNOCENT.

Eve and Floyd’s common neighbors are Amy at A1, Bruce at B1, Gus at C2, Katie at A3, Logan at B3, and Martin at C3. Among those, Bruce is criminal, Martin is innocent, and the clue says Eve and Floyd share an odd number of innocent neighbors, so there must be either 1, 3, or 5 innocents in that shared group. Since Martin already gives one innocent, Amy cannot also be innocent if the rest of the board information for that group is to fit the clue’s required odd total. Zed’s clue also says the only innocent pilot is Eve’s neighbor, so the pilot identities around Eve account for that single innocent-pilot possibility without needing Amy to be innocent. Therefore, we can determine that A1 is CRIMINAL.

The only teachers are Carol at C1, Gus at C2, and Martin at C3. For a teacher to have a criminal directly to the left, the person immediately at B1, B2, or B3 must be criminal respectively. We already know Bruce at B1 is criminal, so Carol definitely counts, and Floyd at B2 is innocent, so Gus definitely does not. Since Amy says exactly 1 teacher fits this condition, Martin cannot also fit it, so the person directly left of Martin, Logan at B3, cannot be criminal. Therefore, we can determine that B3 Logan is INNOCENT.

Eve is at A2, so her neighbors are A1, B1, B2, A3, and B3. Among those, the pilots are only A3 Katie and B3 Logan. The clue says the only innocent pilot is Eve's neighbor, and Logan is already known to be innocent, so Logan must be that one innocent pilot from Eve's neighborhood. That leaves no other innocent pilot, so Katie cannot be innocent. Therefore, we can determine that A3 Katie is CRIMINAL.

In column D, the known criminals are D3, D4, and D5, and Bruce’s clue says that all criminals in that column form one continuous orthogonal chain. Since D3, D4, and D5 are already connected to each other, the only way Isaac at D2 could fit that clue is by also being a criminal connected directly above D3. Katie’s clue matches that as well: Gus at C2 already has three criminal neighbors around him, while Xavi at C5 has three criminal neighbors unless Isaac at D2 is criminal, in which case Gus has four and so has more than Xavi. Therefore, we can determine that D2 is CRIMINAL.

Eve is at A2, so the people to her right are Floyd at B2, Gus at C2, and Isaac at D2. Paula’s clue says Floyd is one of exactly 2 innocents to the right of Eve, and Floyd is already known to be innocent. Isaac is already known to be criminal, so the only way there can be exactly 2 innocents among those three people is for Gus to be the other innocent. Therefore, we can determine that C2 Gus is INNOCENT.

Isaac is at D2, so his neighbors are C1, C2, C3, D1, and D3. Eve says both innocents in column C are Isaac's neighbors, and in column C we already know C2 and C3 are innocent. That means those two are the complete set of innocents in column C, so the remaining person in that column, Carol at C1, cannot be innocent. Therefore, we can determine that C1 is CRIMINAL.

Carol is at C1, so her neighbors are B1 Bruce, B2 Floyd, C2 Gus, D1 David, and D2 Isaac. We already know Bruce and Isaac are criminals, while Floyd and Gus are innocents. For Carol to have more criminal neighbors than innocent neighbors, David must also be a criminal, making 3 criminal neighbors versus 2 innocent neighbors. Therefore, we can determine that D1 is CRIMINAL.

Amy is at A1 and Vicky is at A5, so the clue compares the number of innocent neighbors around those two corner cells. Amy’s only neighbors are Eve, Bruce, and Floyd, and exactly two of them are innocent: Eve and Floyd. So Vicky must also have exactly two innocent neighbors. Vicky’s neighbors are Paula at A4, Ruby at B4, and Wanda at B5. Paula and Ruby are already innocent, so for Vicky to have exactly two innocent neighbors, Wanda cannot be innocent. Therefore, we can determine that B5, Wanda, is CRIMINAL.

In row 5, the three criminals are Wanda at B5, Xavi at C5, and Zed at D5. Paula is at A4, and her neighbors are Katie at A3, Ruby at B4, Vicky at A5, and Wanda at B5, so among those three row 5 criminals, only Wanda is Paula's neighbor. That means the other two row 5 neighbors of Paula cannot be criminals, and one of them is Vicky at A5. Therefore, we can determine that A5 is INNOCENT.