Puzzle Pack #1 Puzzle 42 Answer

Wanda is at B5, so the people above her in column B are Chad at B1, Hal at B2, Linda at B3, and Ryan at B4. Xavi’s clue says Chad is one of two or more innocents above Wanda, which directly includes Chad in that innocent group. Therefore, we can determine that B1, Chad, is INNOCENT.

Wanda is at B5, so the people above her in column B are Chad at B1, Hal at B2, Linda at B3, and Ryan at B4. Xavi says Chad is one of two or more innocents above Wanda, so besides Chad there must be at least one more innocent among B2, B3, and B4. Chad also says all innocents in column B are connected, and since Chad at B1 is innocent, any other innocent in that column must connect to him with no innocent gap. That means B2 has to be innocent. Therefore, we can determine that B2 is INNOCENT.

In column B, Chad at B1 and Hal at B2 are already known to be innocent. Chad’s clue says all innocents in column B form one continuous vertical group, so any other innocent in column B would have to connect to B1 and B2 without a gap. Since B5 is separated from them by B3 and B4, Wanda at B5 cannot be innocent unless B3 and B4 were innocent too, and that would make column B have at least four innocents. Hal’s clue says column C has more innocents than any other column, so no other column can have as many innocents as column C, let alone more. But column C already has only one confirmed innocent, Xavi at C5, so column B cannot be forced up to four innocents. Therefore Wanda cannot be innocent. Therefore, we can determine that B5 is CRIMINAL.

Chad is at B1, so his neighbors are A1, A2, B2, C2, and C1. The clue says exactly 3 of Chad’s neighbors are criminals, and only 1 of those 3 is in column C. Among Chad’s neighbors, the only people in column C are C1 and C2, while B2 is already innocent, so the three neighboring criminals must be A1, A2, and exactly one of C1 or C2. That means both A1 and A2 have to be criminals. Therefore, we can determine that A1 is CRIMINAL and A2 is CRIMINAL.