Puzzle Pack #1 Puzzle 45 Answer

Carol says that Bobby has exactly 2 innocent neighbors, and only 1 of those 2 is also Carol's neighbor. Among Bobby's neighbors, Carol herself is already a known innocent. The only Bobby-neighbors who are also Carol-neighbors are Freya and Gabe, so Carol is the one innocent neighbor of Bobby who is not Carol's neighbor. That means Bobby's other innocent neighbor must be one of Freya or Gabe, not Amy or Ellie. So Amy and Ellie must be criminals.

Bobby has exactly 2 innocent neighbors in total, and Amy and Ellie are already criminal while Carol is already innocent, so the only way to reach 2 innocents around Bobby is for both Freya and Gabe to be innocent. Ellie says an odd number of innocents in column B neighbor Mark. Among Mark's neighbors, the people in column B are Janet, Nicole, and Terry, so Isaac and Susan are not part of that innocent count. Amy says Bobby has more innocent neighbors than Mark, and Bobby has 2 innocent neighbors, so Mark must have fewer than 2 innocent neighbors. Since Isaac and Susan are outside the column B group mentioned by Ellie's clue, this leaves Isaac and Susan as criminal.

Susan’s clue says there are more innocent builders than innocent sleuths. Among the sleuths, Ellie is already criminal, so Laura is the only sleuth who could possibly be innocent. But all three builders, Janet, Nicole, and Terry, are still available to supply the innocent builders that Susan’s clue requires, so the sleuth side cannot include an innocent here. That makes Laura criminal.

Amy’s clue says Bobby has more innocent neighbors than Mark, and Laura’s clue says Mark has more innocent neighbors than Amy. Right now Bobby’s neighbors already include 1 known innocent while Mark’s have 0, and Mark’s neighbors and Amy’s neighbors are both at 0 known innocents. If Gabe were criminal and Bobby were innocent, then Freya, Janet, Nicole, and Terry would have to make both of those “more innocent neighbors” comparisons true at the same time, but they cannot. That opposite assignment clashes with the two clues together. So Gabe at C2 must be innocent, and Bobby at B1 must be criminal.