Puzzle Pack #1 Puzzle 49 Answer

Carol’s clue says Barb has exactly 3 innocent neighbors, and exactly 1 of those innocent neighbors is above Rob. Among Barb’s neighbors who are above Rob, the only people are Carol and Henry. Carol is already known to be innocent, so that one allowed innocent in that above-Rob group is already accounted for. That means Henry cannot be innocent. So Henry must be criminal.

Barb’s still-unknown neighbors are Anna, Eve, and Freya, and exactly one of those three is criminal. But in that group, the only people who can still be that criminal are Eve or Freya. So Anna cannot be the criminal one there. That makes Anna innocent.

Barb’s clue fixes Barb’s neighboring group at exactly three innocents total. Anna and Carol are already innocent there, so among the two still-unknown neighbors in that group, Eve and Freya, exactly one is innocent. Anna’s clue says her own neighboring group, Barb, Eve, and Freya, contains exactly one innocent. Since Eve and Freya already account for the one innocent allowed in Anna’s group, Barb cannot be innocent. So Barb must be criminal.

Barb’s clue says row 2 has exactly one innocent. Carol’s clue fixes Barb’s still-unknown neighboring spots, Eve and Freya, as containing exactly one innocent between them. Since those two are already in row 2, that uses up the single innocent allowed in the whole row. The only other still-unknown person in row 2 outside that pair is Isaac, so Isaac must be criminal.

Barb’s neighbors must contain exactly 3 innocents, and Anna and Carol are already two known innocents there. Among Barb’s neighbors, exactly 1 of those innocents is above Rob, and Carol is already an innocent who is above Rob, so the third innocent neighbor cannot be Freya. That means Eve is the third innocent in Barb’s neighbor group. In row 2, Henry and Isaac are already criminals, and all criminals in that row must be one connected block. With Eve innocent, Freya is the only remaining person in row 2 who can join Henry and Isaac in that criminal block. So Freya must be criminal and Eve must be innocent.

Katie has exactly 2 innocent neighbors in total. The clue also says that none of Katie's innocent neighbors are among the people who are also neighbors of Laura, and in that shared group there are already 0 known innocents. So the remaining unknown people in that shared group, Peter and Rob, cannot be innocent. That makes Peter and Rob criminals.

Peter’s clue directly says that David is one of Henry’s six criminal neighbors. Since the clue itself places David in the criminal group, David must be criminal.

Katie’s neighbors must contain exactly 2 innocents in total, and one of those is already Eve. So among Katie’s still-unknown neighbors, there is exactly 1 innocent left to place: Jose, Laura, and Oscar. In this position, the only people in that group who can still be that innocent are Jose and Oscar, so Laura cannot be the innocent one. So Laura must be criminal.

Katie’s clue leaves exactly 1 innocent among her still-unknown neighbors, and those unknown neighbors are A3 Jose and A4 Oscar. Column A must contain exactly 3 innocents, and it already has Anna and Eve as innocents. So the third innocent in column A has to come from Jose and Oscar, which means column A has already used up all 3 innocent spots before reaching Vicky. This leaves Vicky as criminal.

Katie’s clue fixes that her neighbors contain exactly 2 innocents, and the only unknown neighbors there are Jose and Oscar. Vicky’s clue says the judges must have more innocents than any other profession, and the judge group is Eve, Jose, and Oscar, with Eve already known innocent. So these clues are already using Jose and Oscar as the only judge slots that can raise the judge innocent count. Wally is a doctor, and the doctor profession already has one known innocent, Carol. If Wally were also innocent, doctors would reach 2 innocents, which would block judges from being the unique profession with more innocents than every other profession. That makes Wally criminal.

Wally’s clue says Isaac has more innocent neighbors than Xena. Isaac already has 1 known innocent neighbor, while Xena has 0 known innocent neighbors. Among the unknown neighbors named here, Mary is the only unknown neighbor of Isaac, while Sam and Zed are the unknown neighbors of Xena, so Sam cannot be innocent here. That makes Sam criminal.

Sam’s clue says Peter has exactly 2 innocent neighbors, and exactly 1 of those innocents is in row 4. Among Peter’s neighbors in row 4, the only people are Oscar and Rob, and Rob is already criminal. So the row 4 innocent neighbor Peter needs must be Oscar. That makes Oscar innocent.

Katie’s clue says she has exactly 2 innocent neighbors, and none of those innocent neighbors are among the people she shares as neighbors with Laura. That leaves the only possible innocent-neighbor spots for Katie outside that shared group, namely Eve, Jose, Laura, and Oscar. But Eve and Oscar are already known to be innocent, and Laura is criminal, so Katie’s 2 innocent neighbors are already fully accounted for. Therefore Jose cannot be innocent, so Jose must be criminal.

Wally’s clue says Isaac has more innocent neighbors than Xena. Isaac’s neighbors already include 1 known innocent, while Xena’s neighbors currently have 0 known innocents, and the only unknown in Xena’s neighbors is Zed. So Xena’s neighbors cannot gain an innocent from Zed, or Isaac would no longer have more innocent neighbors than Xena. That makes Zed criminal.

Zed’s clue says there are 5 innocents in total. On the board, the 5 innocents are already Anna, Carol, Eve, Oscar, and no one else shown as innocent. That leaves Xena as criminal.

Sam’s clue says Peter has exactly 2 innocent neighbors, and exactly 1 of those innocent neighbors is in row 4. Among Peter’s neighbors in row 4, Oscar is innocent and Rob is criminal, so the 1 innocent in row 4 is already accounted for. That means Peter must have exactly 1 innocent neighbor who is not in row 4. Among Peter’s neighbors not in row 4, Jose, Laura, Vicky, Wally, and Xena are all criminal, leaving only Katie as the remaining person who can fill that innocent spot. So Katie must be innocent.

Henry's neighbors must contain exactly 6 criminals, and David is confirmed to be one of them. In that neighbor group, Barb, David, Freya, Isaac, and Laura are already known criminals, while Carol and Katie are known innocents. That gives 5 known criminals there, and the only neighbor in that group whose status is still unknown is Mary. So Mary must be criminal.