Puzzle Pack #1 Puzzle 5 Answer

Kevin is at B3, so the people below him are Olof at B4 and Wanda at B5. Olof is already known to be innocent, so among those two people there is currently 1 innocent. Since Olof says the total number of innocents below Kevin is odd, Wanda cannot also be innocent, because that would make 2 innocents below Kevin, which is even. Therefore, we can determine that B5 Wanda is CRIMINAL.

Vicky, Xena, and Zed are all in row 5, with Xena sitting between Vicky at A5 and Zed at D5. Wanda’s clue says there is only one innocent in between Vicky and Zed, so among the two people strictly between them, exactly one must be innocent. Those two people are Wanda at B5 and Xena at C5, and Wanda is already known to be criminal, so the only possible innocent in between is Xena. Therefore, we can determine that C5 is INNOCENT.

Xena is at C5, so her neighbors are B4, C4, D4, B5, and D5. Rose is at D4, so the people to Rose’s left in that row are A4, B4, and C4, and among those, the ones who are also neighboring Xena are only B4 and C4. Xena says exactly one of those is innocent; since B4, Olof, is already known innocent, C4 cannot also be innocent. Therefore, we can determine that C4 is CRIMINAL.

To the right of Vicky are Wanda at B5, Xena at C5, and Zed at D5. We already know Wanda is criminal and Xena is innocent, so among those three people the counts are currently one criminal and one innocent, with Zed undecided. Pam’s clue says there are more criminals than innocents to the right of Vicky, so that can only happen if Zed is also a criminal. Therefore, we can determine that D5 is CRIMINAL.

Olof is at B4, and his neighbors in row 5 are A5, B5, and C5. The clue says an odd number of those neighbors are innocents. We already know B5 is criminal and C5 is innocent, so among those three row-5 neighbors there is currently exactly one innocent unless A5 is also innocent. Since the total must stay odd, A5 cannot be innocent. Therefore, we can determine that A5 is CRIMINAL.

The singers are Brian at B1, Donna at D1, Martin at D3, and Pam at C4. Vicky’s clue says exactly one singer has an innocent immediately to their left. Pam cannot be that singer, because the person directly left of her is Olof at B4, who is innocent, so that already gives us one singer who fits the clue. That means none of the other singers can also have an innocent directly to their left: for Brian that makes Alice at A1 not innocent, and for Martin that makes Lisa at C3 not innocent. Therefore, we can determine that A1 is CRIMINAL and C3 is CRIMINAL.

Gus is at C2, so his neighbors are Brian, Chris, Donna, Frank, Helen, Kevin, Lisa, and Martin. Among those, the criminals already known are Lisa at C3 and Alice at A1 only if she also neighbors Gus does not count here because she is not next to C2; Olof is at B4, whose neighbors are Isaac, Kevin, Lisa, Nicole, Pam, Vicky, Wanda, and Xena. So among the five criminal neighbors of Gus, exactly one can also be a neighbor of Olof, and Lisa is already one such person because C3 touches both Gus and Olof. Kevin is also a neighbor of Olof, so if Kevin were criminal, that would make at least two criminal neighbors of Gus who are also Olof's neighbors, which the clue forbids. Therefore, we can determine that B3 is INNOCENT.

Gus is at C2, so his neighbors are B1, C1, D1, B2, D2, B3, C3, and D3. Among those, the known criminals are Lisa at C3 and, if there are any criminals in row 1, they must be among B1, C1, and D1. Olof is at B4, and his neighbors are A3, B3, C3, A4, C4, A5, B5, and C5, so among Gus's neighboring positions only B3 and C3 are also Olof's neighbors. Lisa says that exactly 1 of the 5 criminals neighboring Gus is Olof's neighbor. Since C3 itself is already one such criminal, none of Gus's other criminal neighbors can be at B3, and Kevin at B3 is already innocent anyway. That means Gus must have exactly 4 other criminal neighbors, and they cannot be B2, D2, or D3, so the only way to reach that total is for all three row 1 neighbors B1, C1, and D1 to be criminals. Kevin's clue then fits, because the criminals in row 1 are B1, C1, and D1, which are connected in one continuous group. Therefore, we can determine that B1 is CRIMINAL.

Martin is at D3, so the people to his left in the same row are A3 Isaac, B3 Kevin, and C3 Lisa. Brian’s clue says Isaac is one of the 2 criminals among those people. Since Kevin is already known to be innocent, the only possible criminals to Martin’s left are Isaac and Lisa. Lisa is already criminal, so Isaac must be the other one. Therefore, we can determine that A3 Isaac is CRIMINAL.

The only guards are Lisa at C3 and Zed at D5, and both are already known criminals, so there are 0 innocent guards. The clue says the number of innocent guards equals the number of innocent singers, so there must also be 0 innocent singers. Among the singers, Brian at B1 is criminal and Martin at D3 is the only one not yet determined, so Martin cannot be innocent. Therefore, we can determine that D3 Martin is CRIMINAL.

In row 1, A1 and B1 are already known criminals. Kevin’s clue says that all criminals in row 1 must form one continuous left-to-right block, so any criminal in that row cannot be separated from A1 and B1 by an innocent person. That means C1 must also be criminal, because if C1 were innocent then the criminal block in row 1 would have to end at B1, and Chris could not be part of any connected group of criminals there. Therefore, we can determine that C1 is CRIMINAL.

Kevin is at B3, and his neighboring squares are A2, B2, C2, A3, C3, A4, B4, and C4. Chris says Kevin is one of two or more innocents neighboring Ethan, so Kevin must be a neighbor of Ethan and there must be at least one other innocent neighbor of Ethan besides Kevin. The only square neighboring Kevin that could also be Ethan is A2, B2, or C2, and among the neighbors shared with Kevin, A3, C3, and C4 are criminals while B4 is already innocent. Since Ethan must have at least two innocent neighbors including Kevin, Ethan must be at B2 so that both Kevin at B3 and Olof at B4 neighbor Ethan, which makes B2 itself Frank. Therefore, we can determine that B2 is INNOCENT.

Alice is at A1, so her neighbors are B1, A2, and B2. We already know B1 is criminal and B2 is innocent, so if Alice's only innocent neighbor is to the left of Helen, that only innocent neighbor must be B2. The person to the left of Helen is therefore B2, which puts Helen at C2. Since A2 is also a neighbor of Alice and Alice has only one innocent neighbor, A2 cannot be innocent. Therefore, we can determine that A2 is CRIMINAL.

Isaac is at A3, so his neighbors are A2, B2, A4, and B4. Among those, A2 is Ethan the speaker and is already a criminal, while B2 and B4 are innocent, so the only way Isaac can have both neighboring criminals is for A4, Nicole, to be the other one. Ethan’s clue also says those two criminals are neighbors of Kevin, and both A2 and A4 do neighbor Kevin at B3, so this fits exactly. Therefore, we can determine that A4 is CRIMINAL.

Frank is at B2, and his neighbors are Alice at A1, Brian at B1, Chris at C1, Ethan at A2, Gus at C2, Isaac at A3, Kevin at B3, and Lisa at C3. Among those, Alice, Brian, Chris, Ethan, Isaac, and Lisa are already known criminals, while Kevin is innocent, so Frank already has 6 criminal neighbors plus Gus. Nicole’s clue says Frank has the most criminal neighbors, which must be uniquely the most; since Lisa at C3 already has 6 known criminal neighbors even without counting Gus, Frank cannot stay tied with her. So Gus must be criminal, giving Frank 7 criminal neighbors and making him uniquely highest. Therefore, we can determine that C2 is CRIMINAL.

Vicky is at A5, so her neighbors are Nicole, Olof, and Wanda. Nicole and Wanda are criminals while Olof is innocent, so Vicky has exactly 2 criminal neighbors. Donna is at D1, and her neighbors are Chris, Gus, and Helen. Chris and Gus are criminals, so for Donna to have the same number of criminal neighbors as Vicky, Helen cannot also be criminal; otherwise Donna would have 3 criminal neighbors instead of 2. Therefore, we can determine that D2, Helen, is INNOCENT.

Gus is at C2, and his five criminal neighbors are B1 Brian, C1 Chris, D1 Donna, C3 Lisa, and D3 Martin. Olof is at B4, so his neighbors are A3 Isaac, B3 Kevin, C3 Lisa, A4 Nicole, C4 Pam, A5 Vicky, B5 Wanda, and C5 Xena. Among Gus's five criminal neighbors, only Lisa is also a neighbor of Olof, so the clue's "only 1" works only if Donna is criminal as well and the full set of five is exactly those five people. Therefore, we can determine that D1 is CRIMINAL.

Helen says there are 15 criminals in total. On the board, 14 people are already known to be criminals and 5 are already known to be innocent, leaving only Rose at D4 still unknown. Since the total must be exactly 15 criminals, Rose has to be the remaining criminal. Therefore, we can determine that D4 is CRIMINAL.