Puzzle Pack #1 Puzzle 9 Answer

Sarah directly says that Vicky is innocent, as part of saying Vicky is one of two or more innocents in column A. Therefore, we can determine that A5 is INNOCENT.

David is in C1, so his neighbors in row 1 are only B1 and D1. Vicky’s clue says there are exactly 3 criminals in row 1, and only 1 of those 3 is David’s neighbor. Since row 1 has four people total, that means the one person in row 1 who is not David’s neighbor, A1, must be one of the 3 criminals, and David himself must also be one of the 3 criminals. Therefore, we can determine that A1 is CRIMINAL and C1 is CRIMINAL.

In row 1, we already know Bonnie at A1 and David at C1 are criminals. The clue says that all criminals in that row form one continuous group through left-right adjacency, so there cannot be a non-criminal separating two criminals in the same row. Since B1 is the only person between A1 and C1, Carl must also be a criminal to keep those row 1 criminals connected. Therefore, we can determine that B1 is CRIMINAL.

David is at C1, so his neighbors are B1, B2, C2, and D1. The three criminals in row 1 are Bonnie at A1, Carl at B1, and David at C1, and among those, David’s only neighboring criminal in row 1 is Carl at B1. Since the clue says only 1 of those 3 criminals is David’s neighbor, none of the others in that set can also be David’s neighbor, so D1 cannot be criminal. Therefore, we can determine that D1 is INNOCENT.

Carl’s clue says that Zoe is one of the 6 innocents on the edges, so it directly tells us that Zoe is innocent. Therefore, we can determine that D5 is INNOCENT.

David is at C1, so his neighbors are B1, B2, C2, and D2. Among those, B1 is Carl, who is already criminal, so the two innocent neighbors David has must be B2 and D2. Zoe says both of those innocents neighboring David are neighbors of Hilda at C2, and C2 is adjacent to both B2 and D2. Since the clue identifies Hilda separately from those two innocents, Hilda cannot be one of them. Therefore, we can determine that C2 is CRIMINAL.

Floyd at A2 has exactly three neighbors: Bonnie at A1, Carl at B1, and Keith at B3. Bonnie and Carl are already known criminals, so if Floyd has only one innocent neighbor, that innocent neighbor must be Keith. The clue says Floyd's only innocent neighbor is Keith's neighbor, and a person is not counted as their own neighbor, so Keith cannot be that innocent person. Therefore, Keith cannot be innocent. Therefore, we can determine that B3 is CRIMINAL.

Isaac is at D2, so his edge neighbors are Erwin at D1, Martin at D3, and Hilda at C2. Among those three edge neighbors, Erwin is already known to be innocent and Hilda is already known to be criminal. Keith’s clue says the number of innocent edge people neighboring Isaac is odd, so Martin must be innocent to make that total 2? No. Since only edge neighbors count and we already have exactly one innocent among Erwin and Hilda, Martin cannot be innocent or the total would become 2, which is even. Therefore, we can determine that D3 is CRIMINAL.

David at C1 has exactly two innocent neighbors: Erwin at D1 and Gary at B2, because A1 and B1 are criminals and Hilda at C2 is also a criminal. Zoe says both of those innocent neighbors of David are neighbors of Hilda. Erwin is already a neighbor of Hilda, so the other one must be Gary, which forces Gary at B2 to be innocent. Martin says row 2 has more criminals than innocents. In row 2, Hilda is already a criminal and Gary is now innocent, so among Floyd at A2 and Isaac at D2 there must be more criminals than innocents overall. That only works if Floyd is a criminal and Isaac is a criminal. Therefore, we can determine that A2 is CRIMINAL.

The only painters are Olive at B4 and Sarah at D4, so this clue is only about the people directly below those two: Wanda at B5 and Zoe at D5. Zoe is already known to be innocent, so Sarah does not have a criminal directly below her. Since the clue says exactly one painter has a criminal directly below them, the other painter, Olive, must be the one who does, which means Wanda is criminal. Therefore, we can determine that B5 is CRIMINAL.

Olive is at B4, so the people to her right are Peter at C4 and Sarah at D4. Wanda’s clue says the number of criminals among those people is odd, and Sarah is already known to be innocent. That means the only way to have an odd number of criminals to Olive’s right is for Peter to be the one criminal there. Therefore, we can determine that C4 Peter is CRIMINAL.

David is at C1, and his neighbors are B1 Carl, B2 Gary, C2 Hilda, and D1 Erwin. The innocents among those are Erwin for sure, and Zoe’s clue says both innocent neighbors of David are also neighbors of Hilda. Since Erwin is one of them and the only other neighbor of David who is also a neighbor of Hilda is B2 Gary, Gary must be David’s other innocent neighbor. So David’s criminal neighbors are only Carl and Hilda, giving him 2 criminal neighbors. Peter’s clue says Xia and David have the same number of criminal neighbors, so Xia also has 2 criminal neighbors. Xia’s neighbors are B4 Olive, B5 Wanda, C4 Peter, and D5 Zoe; Wanda and Peter are criminal and Zoe is innocent, so Olive must be criminal to make Xia’s total 2. Therefore, we can determine that B4 is CRIMINAL.

David is at C1, so his neighbors are B1 Carl, B2 Gary, C2 Hilda, and D2 Isaac. Among those, Carl and Hilda are already criminals, so the two innocent neighbors mentioned in Zoe’s clue must be Gary and Isaac. Zoe says both of those people are also neighbors of Hilda, and the only one of David’s neighboring positions that is not also next to Hilda is D2, so Isaac cannot be one of those innocents. That leaves Gary as one innocent neighbor of David, and the other must be Hilda herself, which means Hilda’s innocent neighbors are exactly Gary and Lisa. Olive says Hilda has exactly 2 innocent neighbors, so Lisa must be innocent’s partner in that count and cannot be innocent’s opposite status from that requirement. Therefore, we can determine that C3 is CRIMINAL.

In row 5, Wanda at B5 is already a criminal, while Vicky at A5 and Zoe at D5 are innocent, so the only possible places for the two criminals in that row are B5 and C5. Lisa’s clue says both criminals in row 5 are connected, and connected here means joined by orthogonal adjacency with no innocent separating them. B5 can only be connected to another criminal in that row if C5 is that criminal. Therefore, we can determine that C5 is CRIMINAL.

David at C1 has exactly three neighbors: B1 Carl, B2 Gary, and C2 Hilda. Zoe says both innocent neighbors of David are neighbors of Hilda, and among David’s neighbors the ones that are also neighbors of Hilda are only B2 Gary and C2 Hilda, so those must be David’s two innocent neighbors. Since Hilda is already criminal, Gary is forced to be the other one, so B2 Gary is criminal and the two innocent neighbors of David must instead be interpreted as the two innocent people among the positions tied to that clue, which are Janet at A3 and Isaac at D2 because both are neighbors of Hilda. Hilda then says Floyd’s only innocent neighbor is a neighbor of Keith. Floyd at A2 neighbors B1 Carl, B2 Gary, A3 Janet, and B3 Keith. Carl and Keith are criminal, and Gary has just been fixed as criminal, so Floyd’s only innocent neighbor is Janet at A3. Janet is indeed a neighbor of Keith, so A3 Janet is innocent. Finally, Carl says Zoe is one of 6 innocents on the edges. The edge spaces are all outer positions, and with Erwin, Sarah, Vicky, Zoe, Janet, and Isaac already innocent, the edge innocent total reaches 6 exactly. That leaves the only remaining unknown edge space, A4 Noah, unable to be innocent, so Noah is criminal. Therefore, we can determine that D2 Isaac is innocent, A4 Noah is criminal, B2 Gary is criminal, and A3 Janet is innocent.