Puzzle Pack #2 Puzzle 44 Answer

Zara’s clue says that the two criminals below Frank are connected. The people below Frank are Jose, Olive, Uma, and Zara, and Zara is already innocent, so the clue can only still affect Jose, Olive, and Uma. Within that group, the clue does not settle every unknown person, but it does settle Olive’s status. So Olive must be criminal.

Olive’s clue says there are exactly 2 criminals to the right of Ruby. That group currently has 0 known criminals, and the only unknown people left there are Stella and Uma. Since those two spots must account for all 2 criminals, Stella and Uma must be criminals.

Zara’s clue says that the criminals below Frank are exactly two people, and those two must be connected. Among the people below Frank, Olive and Uma are already known criminals, Zara is known innocent, and Jose is the only unknown person there. Olive and Uma already make the required connected pair of two criminals below Frank, so Jose cannot also be a criminal. So Jose must be innocent.

Stella’s clue says that Lisa is one of the exactly 2 innocents above Vince. That directly identifies Lisa as innocent. So Lisa must be innocent.

Above Vince, Lisa is already one of the exactly 2 innocents, so there is room for only 1 more innocent among Chad, Gary, and Pam. That remaining innocent must come from Gary and Pam, not Chad. So Chad cannot be innocent. That makes Chad criminal.

Chad’s clue directly says that Xia is one of the four criminals in column C. That means Xia is criminal.

Xia’s clue says Frank is one of Eli’s exactly 3 criminal neighbors. That directly identifies Frank as a criminal. So Frank must be criminal.

Chad’s clue says column C has exactly 4 criminals, and Stella and Xia are already known criminals there. That means among the three unknown people in column C, Eli, Isaac, and Noah, exactly 1 of them is innocent. The only people in that trio who can still be that innocent person are Isaac and Noah, so Eli cannot be the innocent one. So Eli must be criminal.

Above Vince, Chad is criminal, Lisa is innocent, and Gary and Pam are the only unknowns there. Since Lisa is one of exactly 2 innocents above Vince, Gary and Pam cannot be Gary innocent and Pam criminal. That opposite pairing also clashes with the other clue requirements being used here at the same time: Lisa’s neighbors must match Olive’s innocent-neighbor count, row 1 must have more criminals than row 4, column C must contain exactly 4 criminals, Eli’s neighbors must contain exactly 3 criminals, and Ruby’s neighbors must contain exactly 4 innocents. So Gary at A2 must be criminal, and Pam at A4 must be innocent.

Pam’s clue says the people below Denis contain an odd number of innocents. Right now that group has no known innocents, so if Wanda were innocent, the remaining three people there would have to fit that odd-total requirement together with the other active clues. At the same time, Lisa’s neighbors and Olive’s neighbors must have the same number of innocents, and both groups currently already have 1 known innocent. Also, column C must contain exactly 4 criminals, with Eli, Stella, and Xia already criminal, so Isaac and Noah are the only undecided places for that clue. Taking Wanda as innocent makes the same open people involved in these clues unable to satisfy all of those requirements at once. So Wanda cannot be innocent. That makes Wanda criminal.

Wanda’s clue says only one column has exactly 2 innocents. Column D already has exactly 2 innocents, Jose and Zara. Column A also already has 2 known innocents, Lisa and Pam, and Vince is the only unresolved person in that column. So column A cannot stay at exactly 2 innocents, which means Vince cannot be criminal. This leaves Vince as innocent.

Lisa’s neighbors and Olive’s neighbors must contain the same number of innocents. Olive’s neighbors already have 1 known innocent, and because column C has exactly 4 criminals, C2 Isaac and C3 Noah contain exactly 1 innocent, so Olive’s neighbors have 2 innocents in total. Lisa’s neighbors already have 1 known innocent, so B2 Hilda, B3 Mark, and B4 Ruby must also contain exactly 1 innocent. Wanda’s clue says only one column has exactly 2 innocents, and column D already does. If B1 Denis were innocent, then column B would also have exactly 2 innocents: Denis plus the 1 innocent among Hilda, Mark, and Ruby. That cannot happen, so Denis at B1 must be criminal.

Lisa’s clue makes Lisa’s neighbors and Olive’s neighbors have the same number of innocents, and right now each group already has 1 known innocent. Xia’s clue also fixes Eli’s neighborhood at exactly 3 criminals, while Ruby’s clue says Ruby has exactly 4 innocent neighbors and she already has 3 known innocent neighbors, so the remaining open people tied to these clues, Hilda, Isaac, Mark, and Noah, have to fit all of those counts together. If Ruby were innocent, then those same open people would have to satisfy all of those clue requirements at once, but they cannot. So Ruby cannot be innocent. That makes Ruby criminal.

Ruby’s clue says Denis and Uma must have the same number of innocent neighbors. Right now Denis’s neighbors have 0 known innocents, while Uma’s neighbors already have 1 known innocent, Zara, and the only unknown person among Uma’s neighbors is Noah. If Noah were innocent, then Uma’s neighbors would have 2 innocents. But the only other unknown people involved in these clues are Hilda and Isaac in Denis’s neighbor group, and that same set also has to fit Xia’s clue about Eli’s neighbors. Those facts cannot all be satisfied at once if Noah is innocent. So Noah must be criminal.

Chad’s clue says Xia is one of exactly 4 criminals in column C. In column C, Eli, Noah, Stella, and Xia are already the 4 known criminals, and Isaac is the only person there whose status was still unknown. That means the clue’s total of 4 criminals in column C is already complete, so Isaac must be innocent.

Xia's clue says that Frank is one of Eli's exactly 3 criminal neighbors. Eli's neighbors here are Denis, Frank, Hilda, Isaac, and Jose, and among them Denis and Frank are already known criminals while Isaac and Jose are already known innocents. That leaves Hilda as the only neighbor not yet accounted for, and Eli still needs a third criminal neighbor. So Hilda must be criminal.

Jose’s clue says Lisa’s neighbors and Olive’s neighbors must contain the same number of innocent people. Right now, Lisa’s neighbors have 1 known innocent, while Olive’s neighbors have 2, and the only still-unknown person involved in this comparison is Mark among Lisa’s neighbors. So Mark has to be the extra innocent needed to make the two counts equal. That makes Mark innocent.