Puzzle Pack #2 Puzzle 48 Answer

Uma’s clue says there are exactly 2 criminals below Luigi. Right now, there are 0 known criminals there, and the only unknown people below Luigi are Paula and Vince. So those two spots must supply both criminals, which means Paula and Vince must be criminals.

Hilda and Mary’s shared neighbors are Gabe, Isaac, Luigi, and Nick, and Paula’s clue says exactly one person in that shared group is innocent. In that group, the only people who can still be that one innocent are Gabe and Isaac. That means Luigi and Nick cannot be the innocent person named by the clue, so Luigi and Nick must be criminals.

Row 2 has exactly two criminals, and Vince’s clue says those two have to be connected. Among the possible row 2 places, the only connected pair that works is C2 Isaac and D2 Karen. So the row 2 criminals are fixed as Isaac and Karen, which means Flora cannot be part of any connected criminal block that satisfies that clue. That makes Flora innocent.

Row 2 has exactly two criminals, and they must be connected. Also, among the edge neighbors of Chris, namely Betty, Flora, and Karen, an odd number are innocent; since Flora is already innocent, that fixes the innocence in that small group to an odd total. At the same time, Nick’s neighbors are the only neighbor set with exactly 4 innocents, and applying that restriction together with the row 2 rule determines the row 2 pair. This leaves Gabe as innocent and Isaac as criminal.

Amy is one of the people affected by Flora’s claim that only Nick has exactly 4 innocent neighbors and Gabe’s claim that only Isaac has exactly 5 innocent neighbors. If Amy were innocent, then Betty, Chris, Hilda, Karen, Mary, Ollie, Ryan, Stella, Wanda, Xavi, and Ziad would have to fit both of those “only one” neighbor-count conditions at the same time. That cannot be done without breaking the uniqueness required by those two clues. So Amy must be criminal.

Ollie is part of both special neighbor-count clues: Nick’s neighbors must be the only neighbor set with exactly 4 innocents, and Isaac’s neighbors must be the only neighbor set with exactly 5 innocents. At the same time, row 2 must contain exactly two criminals, and those two criminals must be connected, with Gabe already innocent and Isaac already criminal in that row. If Ollie were a criminal, then the remaining open people involved in these clues, including Betty, Chris, Hilda, Karen, Mary, Ryan, Stella, Wanda, Xavi, and Ziad, would have to satisfy all of those requirements together, but they cannot. That contradiction rules out Ollie being a criminal. So Ollie must be innocent.

Nick’s clue says his neighbors contain exactly 4 innocents, and Ollie and Uma are already 2 of them. Row 2 has exactly 2 connected criminals, with Isaac already one of them, so exactly one of Hilda and Karen must be innocent. Among the people above Wanda, there are exactly 2 innocents in total, and exactly 1 of those is Stella’s neighbor, so exactly one of Mary and Ryan must be innocent. If Stella were innocent, then Nick’s neighbors would include Ollie, Uma, Stella, one of Hilda or Karen, and one of Mary or Ryan as innocents. That is at least 5 innocents around Nick, which clashes with Nick being the only one with exactly 4 innocent neighbors. So Stella at C4 must be criminal.

Luigi’s clue makes the edge neighbors of Chris contain an odd number of innocents, and that group is Betty, Flora, and Karen. Flora is already innocent, so Betty and Karen cannot both be innocent or both be criminal. Now test Wanda as innocent. Vince’s neighbors and Flora’s neighbors each currently have 1 known criminal, but Isaac says Vince has more criminal neighbors than Flora, so the remaining unknown neighbors would have to settle that difference while also fitting Flora’s clue that only Nick has exactly 4 innocent neighbors. With Wanda as innocent, the same set of unknown people involved in these clues cannot satisfy all of those requirements together. So Wanda cannot be innocent. That makes Wanda criminal.

Nick’s clue fixes that his neighbors contain exactly 4 innocents, and Gabe’s clue fixes that Isaac’s neighbors contain exactly 5 innocents. Nick’s clue about the people between Betty and Ryan also fixes that both Hilda and Mary are innocents there, with exactly one of them being Stella’s neighbor, namely Mary. With those counts in place, these same clue limits also determine that Karen and Ryan are criminals. Then in Stella’s neighbor group, the known innocents are Ollie, Uma, and Mary, while the remaining unknown neighbors are Xavi and Ziad. Since Stella cannot be another person with exactly 4 innocent neighbors, Xavi and Ziad cannot be innocents here. So Xavi and Ziad must be criminals.

Vince’s neighbors already have 2 known criminals, while Flora’s neighbors have 1, and Flora’s neighbors must still end up with more criminal neighbors than Amy’s neighbors. At the same time, row 2 must contain exactly 2 criminals, and those 2 criminals have to be connected. If Ryan were innocent, then Betty, Chris, Hilda, and Karen would be the only remaining people available to make all of those requirements true together, and they cannot do it. That means Ryan cannot be innocent. So Ryan must be criminal.

Nick’s clue says the two people strictly between Betty and Ryan are both innocents, and exactly one of those innocents is Stella’s neighbor. In that between-group, the only person who is also a neighbor of Stella is Mary. So Mary has to be that one innocent neighbor of Stella. That makes Mary innocent.

Chris's clue says his neighbors contain an odd number of innocents. Right now those neighbors have 1 known innocent, Flora, and the unknown neighbors are Betty, Hilda, and Karen. At the same time, Vince's clue fixes row 2 so that its two criminals must be connected, and the open people involved there are Hilda and Karen alongside Gabe and Isaac. If Betty were criminal, the requirements from these two clues would conflict for the remaining open people Hilda and Karen and could not all be satisfied together. So Betty must be innocent.

Luigi’s clue is about the edge neighbors of Chris. In that relevant group, the people are Betty, Flora, and Karen, and Betty and Flora are already known to be innocent. Since the number of innocents there must be odd, Karen has to be innocent too, making the total 3. So Karen must be innocent.

Vince’s clue says that the two criminals in row 2 are connected. In row 2, Gabe is innocent, Isaac is criminal, and Karen is innocent, so the only still-unknown person in that row is Hilda. For row 2 to have exactly two criminals that are connected, Hilda has to be the second criminal next to Isaac. So Hilda must be criminal.

Flora’s clue says Nick is the only person whose neighbors contain exactly 4 innocents. Nick’s own neighbors do have exactly 4 innocents, so nobody else can also have 4 innocent neighbors. If Chris were innocent, then Betty’s neighbors would have 4 innocents, Flora’s neighbors would have 2 innocents, Hilda’s neighbors would have 4 innocents, Isaac’s neighbors would have 6 innocents, and Karen’s neighbors would have 3 innocents. That gives another exact-4 case besides Nick, which clashes with “Nick is the only one.” So Chris must be criminal.