Clues by Sam Apr 22, 2026 Answer – Full Solution Explained

01.D2 · Karen → CRIMINAL

Row 2 has exactly 3 criminals in total, and exactly 2 of those criminals are Barnie’s neighbors among A2 Frida, B2 Ghani, and C2 Henry. That means exactly 1 criminal in row 2 must be someone who is not Barnie’s neighbor. The only person in row 2 who is not Barnie’s neighbor is D2 Karen, and there are no known criminals already in that non-neighbor group. So D2 Karen must be CRIMINAL.

02.A4 · Quita → CRIMINAL, B4 · Rose → CRIMINAL, D4 · Uma → CRIMINAL

Row 2 must contain exactly 3 criminals, and Karen is already one of them. Terry’s clue says exactly 2 of row 2’s criminals are Barnie’s neighbors, and the row 2 neighbors of Barnie are Frida, Ghani, and Henry, so the other 2 criminals in row 2 have to come from those three people. That means row 2 has 3 criminals in total. Karen’s clue says rows 2 and 4 contain the same number of criminals. Since row 2 therefore has 3 criminals, row 4 must also have 3 criminals. In row 4, Terry is already innocent, so the only way for row 4 to have 3 criminals is for Quita, Rose, and Uma all to be criminals. So Quita, Rose, and Uma must be criminal.

03.C2 · Henry → INNOCENT

Rose’s clue says Diane and Evie have exactly one innocent neighbor in common. Their shared neighbors are Henry and Karen, and Karen is already criminal. That means the one innocent in that shared group has to be Henry. So Henry must be innocent.

04.A2 · Frida → CRIMINAL, B2 · Ghani → CRIMINAL

Row 2 has exactly 3 criminals in total, and exactly 2 of those row 2 criminals are neighbors of Barnie. Among the row 2 neighbors of Barnie, Henry is already innocent, so that group still needs 2 criminals. The only unknown people left in that group are Frida and Ghani. So Frida and Ghani must be criminal.

05.B3 · Mary → CRIMINAL

Ghani’s clue explicitly says that Mary is one of Rose’s exactly 6 criminal neighbors. That directly identifies Mary as a criminal. So Mary must be CRIMINAL.

06.B5 · Wanda → CRIMINAL

Rose’s still-unknown neighbors contain exactly 1 innocent person: Larry, Noah, Vince, Wanda, and Xola. In that group, the only people who can still be that innocent person are Larry, Noah, Vince, and Xola. That means Wanda cannot be the innocent one there, so Wanda must be criminal.

07.C1 · Diane → INNOCENT

Wanda’s clue says Evie has exactly 2 innocent neighbors. Evie’s neighbors already include 1 known innocent, and the only unknown neighbor left there is Diane. That means the one remaining innocent neighbor must be Diane, so Diane must be INNOCENT.

08.D5 · Zach → INNOCENT

Diane’s clue says Xola has exactly 2 innocent neighbors. Among Xola’s neighbors, 1 is already known to be innocent, and the only unknown neighbor left is Zach. So Zach must be the second innocent neighbor, which makes Zach INNOCENT.

09.C3 · Noah → CRIMINAL

Rose’s still-unknown neighbors are A3 Larry, C3 Noah, A5 Vince, and C5 Xola, and exactly 1 of those 4 must be innocent. From the clues and the current board, the only ones in that group who can still be that innocent person are Larry, Vince, and Xola. That means Noah cannot be the innocent one there. So C3 Noah must be criminal.

10.A3 · Larry → CRIMINAL

Rose’s clue says she has exactly 6 criminal neighbors. Among her neighbors, 4 are already known criminals, 1 is already known innocent, and the 3 unknown neighbors are Larry, Vince, and Xola, so exactly 1 of those 3 unknown neighbors must be innocent. From the row clue, the only people in that unknown-neighbor group who can still be innocent are Vince and Xola. That means Larry cannot be the innocent one there, so Larry must be CRIMINAL.

11.A5 · Vince → CRIMINAL, C5 · Xola → INNOCENT

12.D3 · Paula → CRIMINAL

Xola’s clue says exactly 2 of the edge criminals are in row 3, and in that overlap the only people are A3 Larry and D3 Paula. Larry is already known to be a criminal, so that group still needs 1 more criminal. The only unknown person left there is Paula. So Paula must be CRIMINAL.

13.D1 · Evie → CRIMINAL

Frida’s clue says her neighbors contain exactly 1 innocent, and among her still-unknown neighbors that means exactly one of Andre and Barnie is innocent. Xola’s clue fixes the edge cells at exactly 4 innocents total. On the edge, the only still-unknown person outside that Andre-Barnie pair is Evie, while Diane, Xola, and Zach are already known innocents. So Andre and Barnie already account for the last innocent edge spot, and Evie cannot be innocent. That makes Evie criminal.

14.B1 · Barnie → CRIMINAL

Evie’s clue says column B has more criminals than column D. Right now both columns already have 4 known criminals, and the only still-unknown person involved here is Barnie in column B. So column B can only end up with more criminals than column D if Barnie is also a criminal. That makes Barnie CRIMINAL.

15.A1 · Andre → INNOCENT

Quita’s clue says Frida’s neighbors contain exactly 1 innocent person. Right now, Frida’s neighbors have 0 known innocents, and the only unknown neighbor left is Andre. So Andre has to be the one innocent neighbor, which makes Andre innocent.