Clues by Sam Apr 23, 2026 Answer – Full Solution Explained

01.C5 · Xavi → INNOCENT, D5 · Zara → INNOCENT

Linda’s clue says there are exactly 2 innocents in the group that is both in row 5 and neighboring Uma. That shared group contains only Xavi and Zara, and no one there is already known innocent. Since the group still needs 2 innocents and Xavi and Zara are the only people left in it, both of them have to be those 2 innocents. So Xavi and Zara must be INNOCENT.

02.A3 · Mary → CRIMINAL

03.D1 · Gabe → CRIMINAL

04.A4 · Quita → CRIMINAL

05.A5 · Vince → INNOCENT

06.B3 · Noah → CRIMINAL

Vince’s clue says that Noah is one of Ike’s exactly 5 criminal neighbors. That directly places Noah among the criminal neighbors named by the clue. So Noah must be CRIMINAL.

07.B4 · Ruby → CRIMINAL, B2 · Ike → CRIMINAL

Column B is Bonnie, Ike, Noah, Ruby, and Wanda, and the clue says this column has exactly 1 innocent in total. Bonnie and Wanda are the edge-cell people in column B, and from Noah's clue exactly 1 of those two is criminal, so exactly 1 of them is innocent. That already uses up the only innocent allowed in column B, so nobody else in column B can be innocent. So Ike and Ruby must be criminal.

08.C4 · Terry → INNOCENT, C2 · Kumar → INNOCENT

Olga’s clue says her neighbors contain exactly 4 innocents, and among her still-unknown neighbors there is therefore exactly 1 criminal. In that group, the only people who can still be that one criminal are Pam and Uma. That means Kumar and Terry cannot be the criminal in Olga’s unknown-neighbor group. So Kumar and Terry must be INNOCENT.

09.C1 · Donald → CRIMINAL

10.C3 · Olga → INNOCENT

Column C already has 3 known innocents, while column D has 2, and Ike’s clue says column C has more innocents than column D. Ruby’s clue says Olga’s neighbors contain exactly 4 innocents, and those neighbors already include 3 known innocents, with only Pam and Uma still unknown among them. The only unknown people these two clues can still affect are Olga, Pam, and Uma, and together those limits already determine Olga’s status. So Olga must be innocent.

11.B1 · Bonnie → CRIMINAL

12.B5 · Wanda → INNOCENT

Quita’s clue says column B is the only column with exactly one innocent, so column B itself must contain exactly one innocent person. In column B, Bonnie, Ike, Noah, and Ruby are already criminals, and Wanda is the only unknown person left there. That means the one innocent in column B has to be Wanda. So B5 Wanda must be INNOCENT.

13.D3 · Pam → INNOCENT

14.D4 · Uma → CRIMINAL

15.A2 · Hal → CRIMINAL

Pam’s clue says row 2 contains exactly 2 innocents. Row 2 already has those 2 known innocents, Kumar at C2 and Linda at D2. The only unknown person left in that row is Hal at A2, so Hal cannot be innocent. So Hal must be CRIMINAL.

16.A1 · Alex → INNOCENT