Clues by Sam Apr 25, 2026 Answer – Full Solution Explained

01.D5 · Xia → CRIMINAL

Orion’s clue says that Xia is one of the exactly 2 criminals in row 5. Since Xia is explicitly named as one of those criminals, no extra deduction about the rest of the row is needed. So Xia must be criminal.

02.D1 · Dave → INNOCENT, D2 · Isaac → INNOCENT

Xia’s clue says the people above Nick contain exactly 2 innocents. Right now there are 0 known innocents in that group, and the only people left there are Dave and Isaac. Since those two spots must supply all 2 innocents required by the clue, both of them have to be innocent. So Dave and Isaac must be innocent.

03.C3 · Luigi → INNOCENT

Dave’s clue says that Luigi is one of the exactly 2 innocents below Chloe. That directly identifies Luigi as an innocent. So Luigi must be innocent.

04.C4 · Saga → CRIMINAL, A5 · Umar → INNOCENT

Row 5 must contain exactly 2 criminals, and Xia is already one of them. The people below Chloe must contain exactly 2 innocents, and Luigi is already one of them. If Saga were innocent while Umar were criminal, then the remaining people involved here, Helen, Vera, and Wanda, would have to satisfy those clue requirements at the same time, but they cannot. So that opposite pairing is ruled out. That makes Saga criminal and Umar innocent.

05.B4 · Ruth → CRIMINAL, B5 · Vera → CRIMINAL, C5 · Wanda → INNOCENT

06.C2 · Helen → CRIMINAL

Dave’s clue says Luigi is one of exactly 2 innocents below Chloe. Below Chloe are Helen, Luigi, Saga, and Wanda, and among them Luigi and Wanda are already innocent while Saga is criminal. If Helen were innocent too, there would be 3 innocents below Chloe, which conflicts with the clue’s exact total of 2. So Helen must be criminal.

07.A2 · Franco → INNOCENT

Ruth’s clue says Franco is one of the exactly 11 innocents on the edges. That directly identifies Franco as an innocent. So Franco must be innocent.

08.B1 · Betsy → INNOCENT

09.C1 · Chloe → INNOCENT

Ruth's clue says there are exactly 11 innocents on the edges. Among edge cells, 7 are already known innocents and 2 are already known criminals, so the 5 unknown edge people must contain exactly 4 innocents and 1 criminal. That one edge criminal is accounted for by Andre, Joyce, Nick, and Tom, so Chloe is not in the set that can supply the single remaining edge criminal. Therefore Chloe at C1 must be innocent.

10.D4 · Tom → INNOCENT

11.D3 · Nick → INNOCENT

12.B3 · Kumar → INNOCENT

Ruth's clue says the edge cells contain exactly 11 innocents. There are already 10 known innocents on the edge, so the only remaining edge innocents must be Andre and Joyce. Franco's clue says Franco and Ghani have exactly 3 innocent neighbors in common. In their shared neighbor group, Betsy is already innocent, and Andre and Joyce are the other two innocents fixed by the edge clue. That makes the three innocent people in the smaller shared part Andre, Betsy, and Joyce, so the remaining person in the larger shared group, Kumar, must be innocent. So Kumar must be innocent.

13.B2 · Ghani → INNOCENT

Ruth's clue says Franco is one of exactly 11 innocents on the edges. There are already 10 known innocents on the edge, and the only unknown edge people are Andre and Joyce, so those two edge places have to account for the last edge innocent. Nick's clue says Franco's neighbors contain an odd number of criminals. Among Franco's neighbors there are no known criminals, and the unknown neighbors are Andre, Ghani, and Joyce. If Ghani were a criminal, then Andre and Joyce would still have to fit the edge-innocent requirement at the same time, and that clashes with the odd-criminal requirement for Franco's neighborhood. So Ghani must be innocent.

14.A1 · Andre → CRIMINAL

Ghani’s clue says rows 1 and 2 must have the same number of innocents. Row 2 already has 3 innocents, and row 1 also already has 3 known innocents. If Andre were innocent too, row 1 would rise to 4 innocents while row 2 would stay at 3, so the clue would fail. So Andre must be criminal.

15.A3 · Joyce → INNOCENT

Ruth’s clue says Franco is one of exactly 11 innocents on the edges. Among the edge cells, 10 people are already known to be innocent, and Joyce is the only edge person whose status is still unknown. If Joyce were criminal, the edge would have only those 10 innocents, not 11. So Joyce must be innocent.