MediumMay 05, 2026Solved

Clues by Sam May 05, 2026 Answer – Full Solution Explained

A1

👮‍♂️

Adam

cop

B1

👮‍♂️

Chad

cop

C1

👮‍♂️

Denis

cop

D1

👨‍⚖️

Erwin

judge

A2

💂‍♂️

Floyd

guard

B2

🕵️‍♂️

Gabe

sleuth

C2

👩‍💻

Hope

coder

D2

👨‍⚖️

Igor

judge

A3

👩‍🏫

Joy

teacher

B3

💂‍♀️

Katie

guard

C3

👩‍⚕️

Laura

doctor

D3

👨‍⚖️

Martin

judge

A4

💂‍♂️

Olof

guard

B4

👩‍🏫

Penny

teacher

C4

👩‍💼

Quita

clerk

D4

👩‍💼

Rose

clerk

A5

👩‍💻

Sofia

coder

B5

👩‍⚕️

Tina

doctor

C5

🕵️‍♀️

Uma

sleuth

D5

👨‍💼

Will

clerk

Final Board State

This puzzle is fully solved.

All characters have been identified as innocent or criminal based on today's clues.

Final Result
Innocent 14Criminal 6Unknown 0

See how each clue leads to the final result

Just the answer

Skip the reasoning — 6 criminals.

Full walkthrough · Tuesday May 05, 2026

Clues by Sam answer for May 05, 2026 — a Medium solved in 15 steps

Today's Clues by Sam puzzle is rated Medium and resolves with 6 criminals on a 20-cell, 4-column × 5-row grid. The criminals are Adam (A1), Hope (C2), Joy (A3), Laura (C3), Sofia (A5) and Uma (C5); the remaining 14 suspects are innocent.

The deduction chain, in plain English

01.A4 · Olof INNOCENT, C4 · Quita INNOCENT

Denis's clue says exactly 2 innocents are both to the left of Rose and neighboring Penny. That shared group contains only Olof and Quita. Since the clue needs 2 innocents there and those are the only two people in the group, both of them have to fill those two innocent spots. So Olof and Quita must be innocent.

02.D4 · Rose INNOCENT, D5 · Will INNOCENT

Quita’s clue says there are exactly 2 innocents below Martin. Below Martin there are currently 0 known innocents, and the only people there whose identities are not yet known are Rose and Will. Since those two spots still have to supply exactly 2 innocents, both of them have to be innocent. So Rose and Will must be innocent.

03.C5 · Uma CRIMINAL

Will’s clue says Rose has exactly two criminal neighbors, and exactly one of those criminals is also a neighbor of Tina. Among the people who are neighbors of both Rose and Tina, Quita is innocent and the only unknown person left is Uma. So that one criminal in the shared-neighbor group has to be Uma. That makes Uma criminal.

04.B1 · Chad INNOCENT, B5 · Tina INNOCENT

Uma’s clue says exactly 2 corner people have an innocent directly to the right of them. That means there must be 2 such right-hand neighbors accounted for by this clue. The only direct-right neighbors still relevant to that count are Chad at B1 and Tina at B5, so both of those have to be innocent to supply the 2 required cases. So Chad and Tina must be innocent.

05.D1 · Erwin INNOCENT, D2 · Igor INNOCENT

Chad’s clue says exactly 2 judges have an innocent directly above them. The judges involved here are Igor and Martin: Igor has Erwin directly above him, and Martin has Igor directly above him. For those two judge cases to be the 2 that satisfy the clue, the people directly above them must both be innocent, so Erwin and Igor have to be innocent. So Erwin and Igor must be innocent.

06.B2 · Gabe INNOCENT

Erwin’s clue says Gabe is one of the exactly 2 innocents to the left of Igor. Since Gabe is explicitly included among those innocents, Gabe must be innocent. So Gabe must be innocent.

07.B3 · Katie INNOCENT

Hope’s clue says her neighbors contain an odd number of innocents. Right now Hope already has 5 known innocent neighbors, and the only unknown neighbors there are Katie, Laura, and Martin. Rose’s clue says Rose has exactly 2 criminal neighbors in total, and exactly 1 of those criminal neighbors is also Tina’s neighbor. Uma is already one such criminal neighbor of Rose, so Laura and Martin are the remaining people tied to that requirement. If Katie were criminal, then Laura and Martin would have to make both clues true at the same time, but they cannot. So Katie cannot be criminal. That makes Katie innocent.

08.B4 · Penny INNOCENT

09.A1 · Adam CRIMINAL

Tina says only one row has no criminals. Row 4 already has none, since Olof, Penny, Quita, and Rose are all innocent. Row 1 also has no known criminals at the moment, and Adam is the only person there not yet identified, so row 1 cannot be allowed to end with zero criminals too. So Adam must be criminal.

10.A5 · Sofia CRIMINAL

Igor’s clue says row 1 has more innocents than row 5. Row 1 already has 3 innocents, and row 5 currently has 2 innocents. If Sofia were innocent, then row 5 would also have 3 innocents, so row 1 would not have more innocents than row 5. So Sofia must be criminal.

11.D3 · Martin INNOCENT

Sofia's clue says columns B and D have the same number of innocents. Column B already has 5 innocents, while column D has 4 known innocents and only Martin left unknown. If Martin were criminal, column D would stay at 4 innocents, so it could not match column B's 5. So Martin must be innocent.

12.C3 · Laura CRIMINAL

Rose’s neighbors contain exactly 2 criminals. The clue also says exactly 1 of those criminals is Tina’s neighbor, and among the people who are both Rose’s neighbors and Tina’s neighbors, the only criminal is Uma. So the other criminal next to Rose must be someone who is not Tina’s neighbor. Among Rose’s neighbors who are not Tina’s neighbor, Martin and Will are innocent, leaving only Laura to fill that remaining criminal spot. So Laura must be criminal.

13.C2 · Hope CRIMINAL

Martin’s clue says the people above Uma contain exactly 2 criminals. In that group, Laura is already a known criminal, and Denis and Quita are known innocents, so only 1 criminal is accounted for so far. The only person there whose identity is still unknown is Hope, so the missing second criminal has to be Hope. So Hope must be criminal.

14.A2 · Floyd INNOCENT

Erwin’s clue says Gabe is one of exactly 2 innocents to the left of Igor. The people to the left of Igor are Floyd, Gabe, and Hope, and among them Gabe is innocent while Hope is criminal. If Floyd were criminal too, then Gabe would be the only innocent on Igor’s left, which contradicts the clue’s requirement of exactly 2 innocents there. So Floyd must be innocent.

15.A3 · Joy CRIMINAL

Floyd’s clue says there are exactly 14 innocents in the whole board. Right now, 14 people are already known to be innocent, and Joy at A3 is the only person not yet identified. If Joy were innocent too, that would make more than 14 innocents, which clashes with Floyd’s clue. So Joy must be criminal.

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