Puzzle Pack #1 Puzzle 30 Answer

Henry is at C2 and Xia is at C5, so the people above Xia are C1, C2, C3, and C4. Ethan’s clue says Henry is one of the 3 innocents above Xia, which directly places Henry among those innocents. Therefore, we can determine that C2 is INNOCENT.

Henry is at C2 and Xia is at C5, so the people above Xia are Henry at C2, Larry at C3, and Susan at C4. Ethan says Henry is one of the 3 innocents above Xia, which means all three people above Xia are innocents. Since Larry is one of those three people, his identity is fixed. Therefore, we can determine that C3 is INNOCENT.

Column C contains David at C1, Henry at C2, Larry at C3, Susan at C4, and Xia at C5. Larry says there is an odd number of innocents in that column, and we already know Henry and Larry are innocent, so column C must contain either 3 or 5 innocents in total. Ethan says Henry is one of 3 innocents above Xia. The people above Xia are exactly C1, C2, C3, and C4, so that means exactly 3 of those 4 people are innocent, including Henry. Since Henry and Larry are already two of those innocents, exactly one of David or Susan is also innocent, which makes exactly 3 innocents total in column C above Xia. That means Xia cannot also be innocent, because then column C would have 4 innocents, which is not odd. Therefore, we can determine that C5 is CRIMINAL.

Row 5 contains Vicky, Wanda, Xia, and Zed, and the clue says the two criminals in that row are both neighbors of Rose at B4. Rose’s neighbors are A3, B3, C3, A4, C4, A5, B5, and C5, so among row 5 people she neighbors only A5, B5, and C5. Since Xia at C5 is already known to be a criminal, the other criminal in row 5 must be one of A5 or B5, not D5. Therefore, we can determine that D5 is INNOCENT.

Row 5 already has one known criminal, Xia at C5, and Xia says both criminals in row 5 are neighbors of Rose at B4. Rose’s neighbors are A3, B3, C3, A4, C4, A5, B5, and C5, so the other criminal in row 5 must be A5 or B5; D5 cannot be that second criminal, and Zed is already innocent anyway. That means row 5 has exactly two criminals. Zed says row 1 has more criminals than any other row, so row 1 must have more than row 5’s two criminals. Since a row only has four spaces, the only way for row 1 to have more than two is to have three criminals. D1 is already innocent, so the other three people in row 1 must all be criminals. Therefore, we can determine that C1 is CRIMINAL, B1 is CRIMINAL, and A1 is CRIMINAL.

Alex is at A1 and Vicky is at A5, so the people in between them in column A are A2, A3, and A4. The clue says Pam is one of two or more innocents in between Vicky and Alex, which means Pam herself must be one of those innocents. Since Pam is at A4, that fixes Pam's identity. Therefore, we can determine that A4 is INNOCENT.

Henry is in C2 and Xia is in C5, so the people above Xia are C1, C2, C3, and C4. Ethan’s clue says exactly 3 of those 4 people are innocents, and Henry is one of them. We already know C1 is criminal, while Henry at C2 and Larry at C3 are innocent, so the only way to make the total above Xia equal 3 innocents is for C4, Susan, to be innocent as well. Therefore, we can determine that C4 is INNOCENT.

Pam is at A4, and her neighbors are A3, B3, B4, A5, and B5. Her clue says Rose is one of her 4 innocent neighbors, so Rose must be one of those innocent neighbors. Since Rose is at B4 and B4 is next to Pam, this clue directly identifies Rose as innocent. Therefore, we can determine that B4 is INNOCENT.

Rose is at B4. Xia says both criminals in row 5 are Rose's neighbors, and since Xia at C5 is one of those criminals, the other criminal in row 5 must also be next to Rose. Rose's neighbors in row 5 are A5, B5, and C5, so the second criminal in row 5 has to be A5 or B5. Pam is at A4, and her neighbors are Janet at A3, Katie at B3, Rose at B4, and Vicky at A5. Pam says Rose is one of her 4 innocent neighbors, so all four of those neighbors are innocent. That makes Janet and Katie innocent, and it also makes A5 innocent, so the other row 5 criminal next to Rose cannot be A5 and must be B5 instead. Therefore, we can determine that A3 is INNOCENT and B3 is INNOCENT.

Alex is at A1 and Vicky is at A5, so the people in between them are exactly A2, A3, and A4. David says there is an odd number of innocents among those three. We already know A3 and A4 are innocent, so there are already 2 innocents there, which is even, and the only remaining person in that group is A2. To make the total odd, A2 must also be innocent. Therefore, we can determine that A2 is INNOCENT.

Janet’s clue compares the number of criminal neighbors around Ethan at D1 and Xia at C5. Ethan’s neighbors are C1, C2, D2, and C1 is the only criminal among them, so Ethan has 1 criminal neighbor. Xia’s neighbors are B4, C4, D4, B5, and D5, and all of those are already known innocent except D4, so for Ethan to have more criminal neighbors than Xia, Xia must have 0 criminal neighbors. That forces D4 to be innocent. Therefore, we can determine that D4 is INNOCENT.

Rose is at B4, so her neighbors are A3, B3, C3, A4, C4, A5, B5, and C5. Xia’s clue says that both criminals in row 5 are Rose’s neighbors, and since C5 is already one criminal in row 5, the other row 5 criminal must also be one of Rose’s row-5 neighbors, which means it must be A5 or B5, not D5. So in row 5 exactly one of A5 and B5 is criminal, and D5 is not. Ethan at D1 has criminal neighbors at C1 and possibly D2, so Ethan has either 2 or 3 criminal neighbors depending on Isaac. Pam at A4 has neighbors A3, B3, B4, A5, and B5, and among those only A5 or B5 can be criminal, so Pam has exactly 1 criminal neighbor. Terry’s clue says Ethan and Pam have equal numbers of criminal neighbors, so Ethan must also have exactly 1 criminal neighbor; since C1 is already criminal, D2 cannot be criminal. Therefore, we can determine that D2 is INNOCENT.

Ethan is at D1, so his neighbors are C1, C2, and D2. Among them, only C1 is criminal, so Ethan has 1 criminal neighbor. Xia is at C5, and her neighbors are B4, C4, D4, B5, and D5; all of those are already known innocent except Wanda at B5, so Xia has either 0 or 1 criminal neighbor depending on Wanda. Janet says Ethan has more criminal neighbors than Xia, so Xia cannot also have 1 criminal neighbor. That means Wanda cannot be criminal. Therefore, we can determine that B5 is INNOCENT.

Rose is at B4, so her neighbors are A3, B3, C3, A4, C4, A5, B5, and C5. The clue says that both criminals in row 5 are Rose's neighbors. In row 5, the only people who are Rose's neighbors are A5, B5, and C5, and B5 is already innocent while C5 is already a criminal. That means the other criminal in row 5 must be A5. Therefore, we can determine that A5 is CRIMINAL.

Janet is at A3, so her neighbors are Flora, Gary, Katie, Pam, and Rose. Since Flora, Katie, Pam, and Rose are already known innocents, Janet has 4 innocent neighbors plus Gary if Gary is innocent. Nick is at D3, and his neighbors are Henry, Isaac, Larry, Susan, Terry, and Zed, all of whom are already known innocents, so Nick has exactly 6 innocent neighbors. Rose says Nick and Janet have the same number of innocent neighbors, so Janet must also have 6 innocent neighbors. That means Gary has to count as innocent, because Janet already has the other 5 neighboring spots filled and only Gary can raise her innocent-neighbor total to match Nick’s. Therefore, we can determine that B2 is INNOCENT.

Henry is at C2, so his neighboring edge positions are C1, D1, D2, and D3. Isaac’s clue says an odd number of edge innocents neighbor Henry. Among those four neighbors, D1 and D2 are already known innocents, C1 is a known criminal, and only D3 is still unknown. That means Henry currently has 2 known edge innocents next to him, so to make the total odd, D3 must also be innocent. Therefore, we can determine that D3 is INNOCENT.