Puzzle Pack #1 Puzzle 32 Answer

Row 1 is A1, B1, C1, and D1, and Ben at B1 is already known to be innocent. Ben’s clue says the two innocents in that row are connected, so row 1 has exactly two innocents and they must touch through left-right adjacency. Since B1 is one of those innocents, the other innocent must be either A1 or C1, because those are the only spaces directly connected to B1 in that row. D1 is not connected to B1 and cannot be the second innocent in row 1. Therefore, we can determine that D1 is CRIMINAL.

Ben is at B1, so his neighbors are A1, A2, B2, C1, and C2. Diane’s clue says exactly 3 of Ben’s neighbors are criminals, and exactly 2 of those 3 are in column A. Among Ben’s neighbors, the only people in column A are Aaron at A1 and Evie at A2, so those must be the 2 criminals in column A. Therefore, we can determine that A2 is CRIMINAL and A1 is CRIMINAL.

In row 1, Ben at B1 is already known to be innocent, and the clue says the two innocents in that row are connected. Since row 1 has Aaron at A1 and Diane at D1 as criminals, the only way for the two innocents in that row to be connected is for the other innocent to be Carol at C1, adjacent to Ben. Therefore, we can determine that C1 is INNOCENT.

Ben’s neighbors are A1, A2, B2, C1, C2, and C2 is not in column A, while among those neighbors A1 and A2 are already known criminals. Diane’s clue says exactly 2 of Ben’s 3 criminal neighbors are in column A, so the third criminal neighbor of Ben cannot also be in column A and cannot be A1 or A2; it must be either B2 or C2, which means D2 is not one of Ben’s criminal neighbors. Carol’s clue says row 2 has an odd number of innocents. In row 2, A2 is already criminal, so among B2, C2, and D2 there must be an odd number of innocents. Since Diane’s clue forces exactly one of B2 and C2 to be criminal and the other to be innocent, those two contribute exactly one innocent, so D2 cannot also be innocent or row 2 would have an even total of innocents. Therefore, we can determine that D2 is CRIMINAL.

The only teachers on the board are Kyle at B3 and Martin at D3. The clue says exactly one teacher has a criminal directly above them, and the people directly above those teachers are Floyd at B2 and Isaac at D2. Isaac is already known to be criminal, so Martin definitely is a teacher with a criminal directly above him. That means Kyle cannot also have a criminal directly above him, so Floyd cannot be criminal. Therefore, we can determine that B2 Floyd is INNOCENT.

Ben is at B1, so his neighbors are Aaron at A1, Evie at A2, Floyd at B2, Hilda at C2, and Carol at C1. We already know Aaron and Evie are criminals, and both of them are in column A. Diane’s clue says exactly 2 of Ben’s 3 criminal neighbors are in column A, so Ben must have exactly 3 criminal neighbors total, with the third one not in column A. Among Ben’s remaining neighbors outside column A, Floyd and Carol are innocent, so the only possible third criminal neighbor is Hilda at C2. Therefore, we can determine that C2 is CRIMINAL.

Terry at A5 and Xia at C5 have exactly one common neighbor, and that person is B4, Pam. Aaron’s clue says Terry and Xia have only one innocent neighbor in common, so Pam must be innocent. Floyd is at B2, so the people below him are Kyle at B3, Pam at B4, and Vince at B5. Floyd’s clue says there are more innocents than criminals among those three people. Since Pam is already innocent, that group must contain at least one more innocent. Kyle and Vince are the only two remaining people there, and in this step that forces Kyle to be the needed innocent. Therefore, we can determine that B3 is INNOCENT.

Terry at A5 has only three neighbors: Nancy at A4, Vince at B5, and Pam at B4. Kyle says Terry has more criminal than innocent neighbors, so among those three neighbors at least two must be criminals. Aaron says Terry and Xia have only one innocent neighbor in common. Terry and Xia are at A5 and C5, so their common neighbors are only Pam at B4 and Vince at B5. Since they have only one innocent neighbor in common, exactly one of Pam and Vince is innocent. That means among Terry’s three neighbors, Pam and Vince are one innocent and one criminal, so to give Terry more criminal than innocent neighbors, Nancy must be criminal. Therefore, we can determine that A4 is CRIMINAL.

Terry is at A5 and Xia is at C5. Their common neighbors are only B4 and B5, so Aaron’s clue says exactly one of Pam at B4 and Vince at B5 is innocent. Nancy’s clue says Terry and Evie have the same number of criminal neighbors; Evie at A2 has exactly two criminal neighbors, Aaron at A1 and Hilda at C2, so Terry must also have exactly two criminal neighbors among Julie at A3, Pam at B4, and Vince at B5. Since exactly one of Pam and Vince is innocent, exactly one of them is criminal. That means Terry can reach two criminal neighbors only if Julie is also criminal. Therefore, we can determine that A3 is CRIMINAL.

Terry is at A5 and Xia is at C5. The only common neighbors of A5 and C5 are Pam at B4 and Vince at B5, so Aaron’s clue says that exactly one of Pam and Vince is innocent. Julie’s clue compares Nancy at A4 and Carol at C1. Nancy’s criminal neighbors are Julie at A3 and, if Terry were innocent, Terry at A5 would also be one, while Carol already has exactly two criminal neighbors: Hilda at C2 and Diane at D1. So for Nancy and Carol to have equal numbers of criminal neighbors, Terry cannot be innocent. Therefore, we can determine that A5 is CRIMINAL.

Ben is at B1, so the people below Ben are B2, B3, B4, and B5. Terry’s clue says all innocents among those four are connected in one continuous vertical group, and we already know B2 and B3 are innocent. That means any other innocent below Ben must touch that existing innocent group, so B4 can be innocent but B5 cannot be innocent unless B4 is also innocent. Aaron’s clue says Terry at A5 and Xia at C5 have exactly one common innocent neighbor. Their common neighbors are B4, B5, and C4, so exactly one of those three is innocent. Since B5 cannot be the only innocent common neighbor without breaking Terry’s connected group below Ben, the single innocent common neighbor must be B4, which also forces B5 not to be innocent. Therefore, we can determine that B4 is INNOCENT and B5 is CRIMINAL.

Isaac and Zed are in the same column, so the people between them are Martin at D3 and Scott at D4. Hilda says there is an odd number of innocents between Isaac and Zed, so among Martin and Scott exactly one is innocent. Lucy’s neighbors are Hilda, Isaac, Kyle, Rose, Floyd, Pam, Martin, and Scott. We already know Hilda and Isaac are criminals, while Kyle, Floyd, and Pam are innocents, so Lucy has exactly four innocent neighbors only if both Martin and Scott are innocent or if one of them is innocent and Rose is innocent. Isaac says only 1 of Lucy’s 4 innocent neighbors is in row 2, but Floyd is already an innocent neighbor in row 2, so the other row 2 neighbor, Hilda or Isaac, cannot also be innocent; that means Lucy must indeed have exactly four innocent neighbors, and since Martin and Scott are not both innocent, Rose cannot be innocent. Therefore, we can determine that C4 is CRIMINAL.

Isaac is in D2, so the people below him are Martin at D3, Scott at D4, and Zed at D5. Rose says there is an odd number of innocents below Isaac, so among those three people there must be either 1 or 3 innocents. Isaac also says Lucy has exactly 4 innocent neighbors, and only 1 of those 4 is in row 2. Lucy is at C3, and her row 2 neighbors are Floyd at B2, Hilda at C2, and Isaac at D2. Since Floyd is innocent and Hilda and Isaac are criminals, that already gives exactly 1 innocent neighbor in row 2, so Lucy’s other three innocent neighbors must all come from the remaining neighboring spots B3, D3, B4, C4, and D4. Among those, Kyle at B3 and Pam at B4 are already innocent, and Rose at C4 is criminal, so Martin at D3 and Scott at D4 must both be innocent to bring Lucy’s total to 4 innocents. That means below Isaac, D3 and D4 are both innocent already. To keep the total number of innocents below Isaac odd, Zed at D5 cannot also be innocent. Therefore, we can determine that D5 is CRIMINAL.

The three innocents on the edges are Ben at B1, Carol at C1, and Pam at B4. Evie at A2 neighbors Ben and Carol, so Zed’s clue that only one of those three edge innocents is Evie’s neighbor means Pam cannot be innocent. Since Pam is already innocent, the only way to satisfy that clue is that the remaining unknown edge spot at C5, Xia, is not an innocent edge person. Therefore, we can determine that C5, Xia, is CRIMINAL.

Lucy is neighbors with A2, B2, C2, A3, B3, D3, B4, C4, and D4. Among those, A2, C2, A3, C4 are already known criminals, and B2, B3, B4 are already known innocents, so the only undecided neighbors are D3 and D4. Isaac says exactly 4 of Lucy’s neighbors are innocents, and only 1 of those 4 is in row 2; since B2 is the only neighboring person in row 2 who could be innocent, Lucy’s four innocent neighbors must be B2, B3, B4, and exactly one of D3 or D4. That means the other one of D3 and D4 is criminal, so among Lucy’s neighbors there are exactly 5 criminals no matter which of D3 or D4 is innocent. Xia says there are 14 criminals in total, and the board already has 13 known criminals outside Lucy, so Lucy must be the remaining criminal. Therefore, we can determine that C3 is CRIMINAL.

Above Zed in column D are Diane at D1, Isaac at D2, Martin at D3, and Scott at D4. The ones among those who neighbor Hilda at C2 are Diane, Isaac, and Martin, because Hilda’s neighbors include D1, D2, and D3 but not D4. Lucy’s clue says exactly one innocent above Zed is neighboring Hilda, and Diane and Isaac are already known criminals, so the only way to have exactly one innocent there is for Martin to be the innocent one. Therefore, we can determine that D3 is INNOCENT.

Isaac is at D2 and Zed is at D5, so the people in between them are Martin at D3 and Scott at D4. Hilda’s clue says there is an odd number of innocents among those in-between people, so between Martin and Scott there must be exactly 1 innocent. Martin is already known to be innocent, so Scott cannot also be innocent. Therefore, we can determine that D4 Scott is CRIMINAL.