Puzzle Pack #1 Puzzle 35 Answer
A1
👩⚖️
judge
B1
👩🔧
mech
C1
👩💻
coder
D1
👩⚖️
judge
A2
👮♂️
cop
B2
👨🔧
mech
C2
💂♂️
guard
D2
👩💻
coder
A3
👨🌾
farmer
B3
👨⚕️
doctor
C3
👨⚕️
doctor
D3
👩⚕️
doctor
A4
👨💼
clerk
B4
👨⚖️
judge
C4
💂♀️
guard
D4
💂♀️
guard
A5
👮♂️
cop
B5
👨💼
clerk
C5
👩🌾
farmer
D5
👩🔧
mech
Replay Reasoning
Answer Explanation
16 / 16 steps visibleKyle’s clue says that Nick is one of the 4 innocents in column B, so it directly tells us that Nick is innocent. Therefore, we can determine that B4, Nick, is INNOCENT.
Column B contains Bonnie at B1, Frank at B2, Jason at B3, Nick at B4, and Terry at B5. Kyle says Nick is one of 4 innocents in column B, and since Nick is already known innocent, that means exactly four of those five people in column B are innocent. Nick also says all innocents below Bonnie are connected, so the innocents among B2, B3, B4, and B5 must form one continuous vertical block; because B4 is innocent, that connected group cannot skip over B3. Therefore, we can determine that B3 is INNOCENT.
Column B already has Jason at B3 and Nick at B4 confirmed innocent. Kyle’s clue says Nick is one of 4 innocents in column B, so there must be exactly four innocents in that column altogether. Jason’s clue says all innocents in column B are connected, and in a single column that means they must form one unbroken vertical block. Since B3 and B4 are both innocent, the only way to make a connected group of four people in column B is B2, B3, B4, and B5. Therefore, we can determine that B2 is INNOCENT.
Frank says that the two innocents in row 5 are both neighbors of Pam at C4. Pam’s neighbors in row 5 can only be B5, C5, and D5, so the two innocents in row 5 must be among those three people. Sam at A5 is not a neighbor of Pam, so he cannot be one of row 5’s two innocents. Therefore, we can determine that A5 is CRIMINAL.
In row 5, the only people to the left of Zara at D5 are Sam at A5, Terry at B5, and Vicky at C5. Sam says there is an odd number of innocents among those three, and since Sam himself is already known to be criminal, the innocents to Zara's left must be either exactly one of Terry and Vicky or both of them. Frank says the two innocents in row 5 are both neighbors of Pam at C4. The row 5 neighbors of Pam are only B5, C5, and D5, so both row 5 innocents must come from Terry, Vicky, and Zara, which means Sam at A5 is not one of them. That leaves exactly two innocents in row 5 among Terry, Vicky, and Zara. Since the number of innocents to Zara's left must be odd, there must be exactly one innocent among Terry and Vicky, so the second row 5 innocent has to be Zara. Therefore, we can determine that D5 is INNOCENT.
Pam is at C4, and her neighbors are Jason at B3, Kyle at C3, Laura at D3, Nick at B4, Ruth at D4, Terry at B5, Vicky at C5, and Zara at D5. Among those eight, Jason, Kyle, Nick, and Zara are already known innocents, so Pam’s only possible criminal neighbors are Laura, Ruth, Terry, and Vicky. Zara’s clue says Vicky is one of Pam’s 2 criminal neighbors, so Vicky must be one of those criminal neighbors. Therefore, we can determine that C5 is CRIMINAL.
Pam is at C4. The two innocents in row 5 must therefore be neighbors of C4, and among the row 5 people, Pam's neighbors are only B5, C5, and D5. But C5 is already known to be criminal and D5 is already known to be innocent, so the only way for both innocents in row 5 to be Pam's neighbors is for B5 to be the other innocent. Therefore, we can determine that B5 is INNOCENT.
Kyle says that Nick is one of 4 innocents in column B, so column B contains exactly four innocents. In column B, Frank, Jason, Nick, and Terry are already known innocents. That already makes the full set of four innocents for that column, so the only remaining person there, Bonnie at B1, cannot be innocent. Therefore, we can determine that B1 Bonnie is CRIMINAL.
Vicky’s clue says the profession with the uniquely highest number of criminals is judges. We already know one criminal judge nowhere else on the board except the two judges Anna at A1 and Debra at D1, and no judge has been shown innocent, so for judges to beat every other profession, both Anna and Debra must be criminals. That gives judges 2 criminals. Cops are Sam and Eric, and since Sam is already a criminal, Eric cannot also be a criminal or cops would also have 2 and judges would not have the most. Farmers are Sam? No, Sam is a cop; the farmers are Isaac and Vicky, and since Vicky is already a criminal, Isaac cannot also be a criminal for the same reason. Therefore, we can determine that A1 is CRIMINAL, D1 is CRIMINAL, A2 is INNOCENT, and A3 is INNOCENT.
Kyle at C3 and Vicky at C5 can only have two common neighbors: B4 and D4. Terry’s clue says those two common neighbors are innocent, so both B4 and D4 are innocent. Now count criminals by profession using the board. Judges have Anna and Debra as criminals, so judges have 2 criminals. Farmers have only Vicky as a criminal, clerks have none confirmed, guards have none confirmed once D4 is innocent, cops have only Sam, coders have none confirmed, doctors have none, and mechs have only Bonnie. Vicky’s clue says judges have more criminals than any other profession, so no other profession can also reach 2 criminals. Among guards, Vicky is already not a guard, D4 is innocent, and the only remaining guard who could be criminal besides unknowns is Gabe at C2 or Pam at C4. If Gabe were criminal, then the guards could still only have at most 1 criminal unless Pam were also criminal, which would tie judges at 2; Vicky’s clue forbids that tie, so Pam cannot be criminal. That leaves Gabe unable to be criminal as well under this count restriction. Therefore, we can determine that C2 is INNOCENT.
Frank is at B2 and Zara is at D5. Frank’s criminal neighbors are Anna at A1, Bonnie at B1, and Carol at C1, while Zara’s criminal neighbors are Vicky at C5 and Ruth at D4 if Ruth is criminal; the other nearby people are innocent or do not exist. Gabe’s clue says Frank and Zara have the same number of criminal neighbors, so Frank must also have exactly two criminal neighbors, which means Carol at C1 cannot be criminal. Therefore, we can determine that C1 is INNOCENT.
Kyle at C3 and Vicky at C5 have as common neighbors only B4, C4, and D4, because those are the only people who touch both of them. Terry’s clue says exactly 2 of those common neighbors are innocent. Since B4 is already known to be innocent, exactly one of A4’s row-mates C4 and D4 is innocent. Carol’s clue says row 4 has more innocents than row 5. Row 5 already has exactly 2 innocents, Terry at B5 and Zara at D5, so row 4 must have at least 3 innocents. In row 4, B4 is already innocent and exactly one of C4 and D4 is innocent, so Martin at A4 must be the third innocent in that row. Therefore, we can determine that A4 is INNOCENT.
Debra is at D1, so the people below her are D2, D3, D4, and D5. Among those, the innocents are only D5 Zara, and Zara neighbors Kyle at C3, so the number of innocents below Debra who neighbor Kyle is 1, which is odd as Martin says. That means D2, D3, and D4 cannot be innocent, and since D3 Laura is already unknown while D4 Ruth is also unknown, D2 Helen is forced to be one of the non-innocents below Debra. Therefore, we can determine that D2 is CRIMINAL.
Bonnie says there are 7 criminals in total. On the board, we already know 7 criminals: Anna at A1, Bonnie at B1, Debra at D1, Helen at D2, Sam at A5, Vicky at C5, and no one else besides the two unknowns Pam and Ruth could increase that count. So there cannot be any additional criminals among the unknown people. Zara’s clue says Vicky is one of Pam’s 2 criminal neighbors, which means Pam does have criminal neighbors, but Bonnie’s total shows Pam herself cannot be an extra criminal. Therefore, we can determine that C4 is INNOCENT.
Kyle is at C3 and Vicky is at C5, so their common neighbors are the people next to both of them: B4 Nick, C4 Pam, D4 Ruth, B5 Terry, and D5 Zara. Terry’s clue says exactly 2 of those common neighbors are innocent. We already know Nick, Pam, Terry, and Zara are innocent, so that is 4 innocent common neighbors unless Ruth is criminal. Therefore, we can determine that D4 Ruth is CRIMINAL.
Pam is at C4, so her neighbors are B3, C3, D3, B4, D4, B5, C5, and D5. From the board, among those neighbors D4 is Ruth, who is criminal, and C5 is Vicky, who is also criminal. Zara’s clue says Vicky is one of Pam’s 2 criminal neighbors, so Pam has exactly those two criminal neighbors and no others. Since Laura at D3 is also Pam’s neighbor, Laura cannot be criminal. Therefore, we can determine that D3 is INNOCENT.