Puzzle Pack #1 Puzzle 37 Answer
A1
👩💻
coder
B1
👩🎨
painter
C1
👩🎨
painter
D1
👩🎨
painter
A2
👨💻
coder
B2
👨✈️
pilot
C2
👨🍳
cook
D2
👩🍳
cook
A3
👷♂️
builder
B3
👷♂️
builder
C3
👷♀️
builder
D3
💂♂️
guard
A4
👮♂️
cop
B4
👮♂️
cop
C4
👩🍳
cook
D4
👮♂️
cop
A5
👩🏫
teacher
B5
👨🏫
teacher
C5
💂♀️
guard
D5
👩✈️
pilot
Replay Reasoning
Answer Explanation
Sofia’s clue says that Wally is one of Ronald’s 6 criminal neighbors. That directly identifies Wally as a criminal. So Wally must be criminal.
Sofia’s clue says Ronald has exactly 6 criminal neighbors. Among Ronald’s neighbors, Wally is already a known criminal and Sofia is already a known innocent, so the 6 still-unknown neighbors contain exactly 1 innocent person. In that unknown-neighbor group, the only people who can still be that one innocent are Kevin, Larry, Mary, Vicky, and Xia. That means Paul cannot be the innocent person there, so Paul must be criminal.
Sofia’s clue says Ronald has exactly 6 criminal neighbors. Among Ronald’s five still-unknown neighbors, that means exactly 1 of them is innocent: Kevin, Larry, Mary, Vicky, and Xia. But the only people in that group who can still be that one innocent are Kevin, Mary, Vicky, and Xia, so Larry cannot be the innocent one there. So Larry must be criminal.
Ronald’s neighbors must contain exactly 6 criminals, and among the four still-unknown neighbors of Ronald that means there is exactly 1 innocent: Kevin, Mary, Vicky, and Xia. From these clues, the only people in that group who can still be that one innocent are Vicky and Xia. So Kevin and Mary cannot be the innocent one in Ronald’s unknown-neighbor group. Therefore Kevin and Mary must be criminals.
Unlock to view the remaining 13 steps.
Answer (spoilers)
Unlock this puzzle to reveal the final answer.