Puzzle Packs/Puzzle Pack #2/Puzzle 29

Puzzle Pack #2 Puzzle 29 Answer

Hard·Puzzle 29·Locked
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A1

🕵️‍♀️

Anna

sleuth

B1

👷‍♂️

Bruce

builder

C1

👩‍🏫

Carol

teacher

D1

👷‍♀️

Debra

builder

A2

👨‍✈️

Erwin

pilot

B2

👨‍✈️

Frank

pilot

C2

👨‍🏫

Gabe

teacher

D2

👩‍🏫

Hope

teacher

A3

👨‍✈️

Isaac

pilot

B3

👩‍⚖️

Katie

judge

C3

👨‍⚖️

Luigi

judge

D3

👩‍⚖️

Maria

judge

A4

👩‍🎤

Nicole

singer

B4

🕵️‍♂️

Peter

sleuth

C4

👩‍🎤

Ruby

singer

D4

👩‍🎤

Sarah

singer

A5

👨‍🔧

Terry

mech

B5

👨‍🎨

Vince

painter

C5

👩‍🎨

Wanda

painter

D5

👨‍🔧

Zed

mech

Replay Reasoning

Step 1 of 4
Step Result
C4 · Ruby is INNOCENT
C5 · Wanda is INNOCENT
Why this is true
Sarah is at D4 and Vince is at B5, so their common neighbors are exactly C4 Ruby, C5 Wanda, and C4’s other overlap does not exist because only positions neighboring both count. Terry’s clue says Sarah and Vince have 2 innocent neighbors in common, so among those shared neighbors, exactly two are innocent. The only shared neighbors of D4 and B5 are Ruby at C4 and Wanda at C5, so those two must be the 2 innocent common neighbors Terry is talking about. Therefore, we can determine that C4 is INNOCENT and C5 is INNOCENT.
Based on this clue:
"Sarah and Vince have 2 innocent neighbors in common" Terry (A5)
Progress
Innocent 2·Criminal 0·Unknown 18

Answer Explanation

4 / 17 steps visible
Step 1

Sarah is at D4 and Vince is at B5, so their common neighbors are exactly C4 Ruby, C5 Wanda, and C4’s other overlap does not exist because only positions neighboring both count. Terry’s clue says Sarah and Vince have 2 innocent neighbors in common, so among those shared neighbors, exactly two are innocent. The only shared neighbors of D4 and B5 are Ruby at C4 and Wanda at C5, so those two must be the 2 innocent common neighbors Terry is talking about. Therefore, we can determine that C4 is INNOCENT and C5 is INNOCENT.

Step 2

Isaac is at A3, so the people in column B who neighbor him are B2 and B3. Ruby says an odd number of those two are innocent, so exactly one of Frank and Katie is innocent. Katie is at B3, and her six neighbors are A2, B2, C2, A3, C3, and B4. Among those, the only neighbors in column B are B2 and B4, and Wanda says exactly one of Katie’s innocent neighbors is in column B. That means Katie has innocent neighbors, so Katie herself cannot be innocent, because an innocent Katie would have 6 innocent neighbors total and then more than one of them would have to be in column B. Therefore, we can determine that B3 is CRIMINAL.

Step 3

Isaac is at A3, so his neighbors in column B are B2, B3, and B4. Ruby says an odd number of those three are innocent, and Katie at B3 is already known to be criminal, so among B2 and B4 exactly one must be innocent. Katie’s clue is about the people below Bruce in column B, namely Frank at B2, Katie at B3, Peter at B4, and Vince at B5. Since Katie is criminal and exactly one of Frank and Peter is innocent, those first three people below Bruce contain either two criminals and one innocent or three criminals. For there to be more criminals than innocents among all four people below Bruce, Vince must also be criminal. Therefore, we can determine that B5 is CRIMINAL.

Step 4

The people in column B are Bruce at B1, Frank at B2, Katie at B3, Peter at B4, and Vince at B5. Vince says every column has at least 2 innocents, and in column B we already know Katie and Vince are criminals, so the only possible innocents there must come from Bruce, Frank, and Peter. Ruby says an odd number of innocents in column B neighbor Isaac at A3. Isaac’s neighbors in column B are only Frank at B2, Katie at B3, and Peter at B4. Since Katie is criminal, the innocents among those neighboring column-B people are just Frank and Peter, so an odd number means exactly one of them is innocent. That gives column B only one innocent among Frank and Peter, so to reach Vince’s minimum of 2 innocents in the column, Bruce must be innocent. Therefore, we can determine that B1 is INNOCENT.

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Answer (spoilers)

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