Puzzle Packs/Puzzle Pack #2/Puzzle 29
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Puzzle Pack #2 Puzzle 29 Answer

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A1

🕵️‍♀️

Anna

sleuth

B1

👷‍♂️

Bruce

builder

C1

👩‍🏫

Carol

teacher

D1

👷‍♀️

Debra

builder

A2

👨‍✈️

Erwin

pilot

B2

👨‍✈️

Frank

pilot

C2

👨‍🏫

Gabe

teacher

D2

👩‍🏫

Hope

teacher

A3

👨‍✈️

Isaac

pilot

B3

👩‍⚖️

Katie

judge

C3

👨‍⚖️

Luigi

judge

D3

👩‍⚖️

Maria

judge

A4

👩‍🎤

Nicole

singer

B4

🕵️‍♂️

Peter

sleuth

C4

👩‍🎤

Ruby

singer

D4

👩‍🎤

Sarah

singer

A5

👨‍🔧

Terry

mech

B5

👨‍🎨

Vince

painter

C5

👩‍🎨

Wanda

painter

D5

👨‍🔧

Zed

mech

Replay Reasoning

Step 1 of 4
Step Result
C4 · Ruby is INNOCENT
C5 · Wanda is INNOCENT
Why this is true
Terry’s clue says Sarah and Vince have exactly 2 innocent neighbors in common. The shared neighbor group is just Ruby and Wanda, and that group still needs 2 innocents. Since Ruby and Wanda are the only people in that shared group, both of them have to supply those 2 innocents. So Ruby and Wanda must be innocent.
Based on this clue:
"Sarah and Vince have 2 innocent neighbors in common" Terry (A5)
Progress
Innocent 2·Criminal 0·Unknown 18
Full walkthrough

Answer Explanation

4 / 17 steps visible
01 · Step 1

Terry’s clue says Sarah and Vince have exactly 2 innocent neighbors in common. The shared neighbor group is just Ruby and Wanda, and that group still needs 2 innocents. Since Ruby and Wanda are the only people in that shared group, both of them have to supply those 2 innocents. So Ruby and Wanda must be innocent.

02 · Step 2

Ruby’s clue says an odd number of Isaac’s neighbors in column B are innocent, and that group is exactly Frank, Katie, and Peter. Wanda’s clue says Katie has exactly 6 innocent neighbors in total, and exactly 1 of those innocent neighbors is in column B, which means among the column B people relevant to Katie’s clue, only Frank or Peter can be that innocent one. So Katie cannot be one of the innocent people in that Isaac-and-column-B group. That makes Katie criminal.

03 · Step 3

Katie’s clue says there are more criminals than innocents below Bruce. The people below Bruce in column B are Frank, Katie, Peter, and Vince, and Katie is already a known criminal with no known innocents among those people. Ruby’s clue says an odd number of the people in column B who neighbor Isaac are innocents; those people are Frank, Katie, and Peter, and since Katie is criminal, exactly one of Frank or Peter is innocent. That gives at most one innocent among the people below Bruce before Vince is counted, so Vince has to be a criminal for the group below Bruce to still have more criminals than innocents. So Vince must be criminal.

04 · Step 4

Ruby’s clue says the number of innocents in the overlap of column B and Isaac’s neighbors is odd. That overlap is exactly Frank, Katie, and Peter, and Katie is already criminal, so among Frank and Peter there must be an odd number of innocents. Vince’s clue says every column has at least 2 innocents, so column B must contain at least 2 innocents among Bruce, Frank, and Peter, since Katie and Vince are already criminals. If Bruce were criminal, then Frank and Peter would have to provide those innocents for column B, but that clashes with Ruby’s odd-number condition on Frank and Peter. So Bruce at B1 must be innocent.

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