Puzzle Pack #2 Puzzle 29 Answer
A1
🕵️♀️
sleuth
B1
👷♂️
builder
C1
👩🏫
teacher
D1
👷♀️
builder
A2
👨✈️
pilot
B2
👨✈️
pilot
C2
👨🏫
teacher
D2
👩🏫
teacher
A3
👨✈️
pilot
B3
👩⚖️
judge
C3
👨⚖️
judge
D3
👩⚖️
judge
A4
👩🎤
singer
B4
🕵️♂️
sleuth
C4
👩🎤
singer
D4
👩🎤
singer
A5
👨🔧
mech
B5
👨🎨
painter
C5
👩🎨
painter
D5
👨🔧
mech
Replay Reasoning
Answer Explanation
4 / 17 steps visibleSarah is at D4 and Vince is at B5, so their common neighbors are exactly C4 Ruby, C5 Wanda, and C4’s other overlap does not exist because only positions neighboring both count. Terry’s clue says Sarah and Vince have 2 innocent neighbors in common, so among those shared neighbors, exactly two are innocent. The only shared neighbors of D4 and B5 are Ruby at C4 and Wanda at C5, so those two must be the 2 innocent common neighbors Terry is talking about. Therefore, we can determine that C4 is INNOCENT and C5 is INNOCENT.
Isaac is at A3, so the people in column B who neighbor him are B2 and B3. Ruby says an odd number of those two are innocent, so exactly one of Frank and Katie is innocent. Katie is at B3, and her six neighbors are A2, B2, C2, A3, C3, and B4. Among those, the only neighbors in column B are B2 and B4, and Wanda says exactly one of Katie’s innocent neighbors is in column B. That means Katie has innocent neighbors, so Katie herself cannot be innocent, because an innocent Katie would have 6 innocent neighbors total and then more than one of them would have to be in column B. Therefore, we can determine that B3 is CRIMINAL.
Isaac is at A3, so his neighbors in column B are B2, B3, and B4. Ruby says an odd number of those three are innocent, and Katie at B3 is already known to be criminal, so among B2 and B4 exactly one must be innocent. Katie’s clue is about the people below Bruce in column B, namely Frank at B2, Katie at B3, Peter at B4, and Vince at B5. Since Katie is criminal and exactly one of Frank and Peter is innocent, those first three people below Bruce contain either two criminals and one innocent or three criminals. For there to be more criminals than innocents among all four people below Bruce, Vince must also be criminal. Therefore, we can determine that B5 is CRIMINAL.
The people in column B are Bruce at B1, Frank at B2, Katie at B3, Peter at B4, and Vince at B5. Vince says every column has at least 2 innocents, and in column B we already know Katie and Vince are criminals, so the only possible innocents there must come from Bruce, Frank, and Peter. Ruby says an odd number of innocents in column B neighbor Isaac at A3. Isaac’s neighbors in column B are only Frank at B2, Katie at B3, and Peter at B4. Since Katie is criminal, the innocents among those neighboring column-B people are just Frank and Peter, so an odd number means exactly one of them is innocent. That gives column B only one innocent among Frank and Peter, so to reach Vince’s minimum of 2 innocents in the column, Bruce must be innocent. Therefore, we can determine that B1 is INNOCENT.
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Answer (spoilers)
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