Puzzle Pack #2 Puzzle 31 Answer

Olivia is at A4, so the people to her right are exactly Paula at B4, Rose at C4, and Terry at D4. Jason’s clue says Rose is one of 3 innocents to the right of Olivia, so those three people to Olivia’s right must be the 3 innocents, including Rose. Therefore, we can determine that B4 is INNOCENT, C4 is INNOCENT, and D4 is INNOCENT.

Alex’s neighbors are Barnie, Ellie, and Flora. Rose says an odd number of Alex’s neighboring people are innocent, so among those three, either exactly one or all three are innocent. Isaac’s neighbors are Barnie, Chad, Donald, Flora, Jason, Logan, Mary, and Rose. Jason and Rose are already known innocents, and Terry’s clue says exactly 1 of Isaac’s 6 innocent neighbors is a mech. Since Barnie and Flora are the only mechs among Isaac’s neighbors, exactly one of Barnie and Flora is innocent. That means Barnie and Flora cannot both be innocent, so Alex cannot have all three neighbors innocent. Therefore Alex has exactly one innocent neighbor among Barnie, Ellie, and Flora. Since exactly one of Barnie and Flora is innocent, Ellie cannot be innocent. Therefore, we can determine that A2 is CRIMINAL.

Isaac’s neighbors are Barnie, Chad, Donald, Flora, Jason, Logan, Mary, and Rose. Among those, Jason and Rose are already known to be innocent, and the clue says that exactly one innocent neighbor of Isaac is a mech. Since Barnie and Flora are the only mech neighbors Isaac has, at most one of them can be innocent. Ellie’s clue says the profession with the most criminals is mech. Ellie herself is already a criminal and is a mech, so for mechs to be the unique profession with the most criminals, there must be another criminal mech somewhere. In the current position, that extra criminal mech cannot be both Barnie and Flora being innocent, so the remaining undetermined mech outside Isaac’s two mech neighbors, Kay at A3, must be criminal. Therefore, we can determine that A3 is CRIMINAL.

Chad is at C1, so the people below Chad are Isaac at C2, Mary at C3, Rose at C4, and Xavi at C5. Kay’s clue says that the innocents among those four are exactly two people, and those two must be connected by orthogonal adjacency. Rose is already known to be innocent, and among those four the only squares orthogonally connected to C4 are C3 and C5, so one of Mary or Xavi must be the other innocent. That leaves Isaac unable to be one of the two innocents below Chad. Therefore, we can determine that C2 is CRIMINAL.