Puzzle Pack #2 Puzzle 39 Answer
A1
👩🌾
farmer
B1
👩🌾
farmer
C1
💂♀️
guard
D1
👩✈️
pilot
A2
👨💼
clerk
B2
👮♂️
cop
C2
🕵️♀️
sleuth
D2
👷♂️
builder
A3
👩💼
clerk
B3
🕵️♂️
sleuth
C3
🕵️♂️
sleuth
D3
💂♂️
guard
A4
👨✈️
pilot
B4
👮♀️
cop
C4
👩🌾
farmer
D4
👩💻
coder
A5
👩💼
clerk
B5
👮♂️
cop
C5
👷♂️
builder
D5
👩💻
coder
Replay Reasoning
Answer Explanation
Henry’s clue says that Wally is one of Vicky’s exactly 2 criminal neighbors. That directly identifies Wally as a criminal. So Wally must be criminal.
Wally’s clue says there are exactly 3 innocents below Donna. Below Donna, there is already 1 known innocent, and the only unknown people left there are Nick and Stella. That means the 2 remaining innocent spots below Donna have to be Nick and Stella. So Nick and Stella must be innocent.
Henry’s clue says that Wally is one of Vicky’s exactly 2 criminal neighbors. Among Vicky’s neighbors, Stella is already innocent and Wally is already one criminal, so the only still-unknown neighbor left in that group is Rob. That means Rob has to be the second criminal neighbor Vicky has. So Rob must be criminal.
Nick’s clue says Stella has exactly 3 innocent neighbors, and exactly 2 of those innocent neighbors also neighbor Joy. In the overlap between Stella’s neighbors and Joy’s neighbors, the only people are Nick, who is already innocent, and Ollie. That overlap still needs 1 more innocent person, and Ollie is the only unknown person left there. So Ollie must be innocent.
Stella's neighbors must contain exactly 3 innocents in total, and 2 of those are already Nick and Ollie, so among Stella's four still-unknown neighbors there is room for exactly 1 more innocent. In that unknown group, the only people who can still be that innocent are Lisa, Tina, or Vicky. That means Xavi cannot be the innocent one in that group. So Xavi must be criminal.
Above Zoe, all criminals have to form one connected block. The three people strictly between Freya and Zoe are Kyle, Paul, and Uma, and that group contains exactly two criminals. With exactly two criminals among Kyle, Paul, and Uma, the only connected criminal blocks that fit are Kyle and Paul, Freya and Kyle and Paul, or Paul and Uma. In every one of those working blocks, Paul is included. So Paul must be criminal.
Paul's clue says Eve has exactly 4 innocent neighbors, and exactly 2 of those innocent neighbors are above Stella. Among Eve's neighbors who are above Stella, Henry is already known to be innocent, and the only other person there is Donna. That means the above-Stella group still needs 1 more innocent, so Donna must be innocent.
Eve’s neighbors must contain exactly 4 innocents, and Donna and Henry are already known innocents there, so among the three still-unknown neighbors of Eve, exactly 1 is criminal. In that unknown trio, the only people who can still be that criminal are Joy and Kyle. So Freya cannot be the criminal one in that group. That makes Freya innocent.
Eve’s clue says her neighbors contain exactly 4 innocents, and exactly 2 of those innocents are above Stella. Those 2 are already Donna and Henry, so among Eve’s other neighboring unknowns, Joy and Kyle, exactly one must be innocent. Donna’s clue says row 2 has an odd number of innocents, and row 2 already has Henry as 1 known innocent. Since Joy and Kyle contribute exactly one more innocent in that row, Gabe must be the additional innocent that makes the row’s total odd. So Gabe must be innocent.
Paul’s clue makes Eve’s neighbors contain exactly one criminal, and that one criminal is among Joy and Kyle. So within Freya’s neighbors, the pair Joy and Kyle already accounts for exactly one criminal, which is an odd number. Freya’s clue says her neighbors must contain an odd number of criminals. Since Joy and Kyle already provide that odd count, the only other neighbor, Eve, cannot also be a criminal without making the total even. So Eve must be innocent.
Stella’s neighbors must contain exactly 3 innocents in total, and 2 of those are already known to be Nick and Ollie, so among Stella’s still-unknown neighbors A3 Lisa, C4 Tina, and A5 Vicky there is exactly 1 innocent. In that three-person group, the only ones who can still be that innocent are Tina and Vicky. So Lisa cannot be the innocent one there. That makes Lisa criminal.
Lisa's clue says rows 1 and 2 have the same number of criminals. Row 1 currently has no known criminals, and the only unresolved person left in that row is Betty. From Paul's clue, Eve's neighbors contain exactly 1 criminal among Joy and Kyle, so row 2 gains exactly 1 criminal. Therefore row 1 must also gain exactly 1 criminal, and since Betty is the only open spot there, Betty must be criminal.
Betty’s clue says column A has exactly one innocent. In column A, Gabe is already that one known innocent, and Vicky is the only unknown person left there. So Vicky cannot be innocent. That makes Vicky criminal.
Nick’s clue says Stella has exactly 3 innocent neighbors, and exactly 2 of those innocent neighbors also neighbor Joy. Those 2 are already identified as Nick and Ollie. So Stella’s neighbors still need exactly 1 more innocent who is not a neighbor of Joy. Among Stella’s neighbors who are not neighbors of Joy, everyone is already a criminal except Tina, so Tina must be innocent.
Ollie says only one row has exactly 3 criminals. Row 5 already has Vicky, Wally, and Xavi as criminals, so if Zoe were also a criminal then row 5 would have 4 criminals instead of exactly 3. That means the row with exactly 3 criminals must be some other row, so Zoe cannot be a criminal. So Zoe must be innocent.
Between Freya and Zoe, there must be exactly one innocent, and among the people there, the only unknowns are Kyle and Uma. Paul's neighbors must contain an odd number of criminals, and among those neighbors, the only unknowns are Joy, Kyle, and Uma. If Joy were criminal, then Kyle and Uma would be the same two people who must both finish the Freya-to-Zoe count and the criminal-neighbor count for Paul at the same time, but they cannot satisfy both of those requirements together. So Joy cannot be criminal. That makes Joy innocent.
Paul’s clue fixes Eve’s neighboring group at exactly 4 innocents in total. It also says exactly 2 of those innocents are above Stella, and those 2 are already Donna and Henry. That leaves the neighbors not above Stella as Freya, Joy, and Kyle, and Freya and Joy already account for the 2 innocents allowed in that remainder. So Kyle must be criminal.
Xavi’s clue says there is exactly one innocent between Freya and Zoe. Among the people strictly between them, there are currently no known innocents, and the only unknown person left there is Uma. So Uma must be innocent.