Puzzle Packs/Puzzle Pack #2/Puzzle 39
HardPuzzle 39

Puzzle Pack #2 Puzzle 39 Answer

A1

👩‍🌾

Betty

farmer

B1

👩‍🌾

Donna

farmer

C1

💂‍♀️

Eve

guard

D1

👩‍✈️

Freya

pilot

A2

👨‍💼

Gabe

clerk

B2

👮‍♂️

Henry

cop

C2

🕵️‍♀️

Joy

sleuth

D2

👷‍♂️

Kyle

builder

A3

👩‍💼

Lisa

clerk

B3

🕵️‍♂️

Nick

sleuth

C3

🕵️‍♂️

Ollie

sleuth

D3

💂‍♂️

Paul

guard

A4

👨‍✈️

Rob

pilot

B4

👮‍♀️

Stella

cop

C4

👩‍🌾

Tina

farmer

D4

👩‍💻

Uma

coder

A5

👩‍💼

Vicky

clerk

B5

👮‍♂️

Wally

cop

C5

👷‍♂️

Xavi

builder

D5

👩‍💻

Zoe

coder

Replay Reasoning

Step 1 of 18
Step Result
B5 · Wally is CRIMINAL
Why this is true
Henry’s clue says that Wally is one of Vicky’s exactly 2 criminal neighbors. That directly identifies Wally as a criminal. So Wally must be criminal.
Based on this clue:
"Wally is one of Vicky's 2 criminal neighbors" Henry (B2)
Progress
Innocent 1·Criminal 1·Unknown 18
Full walkthrough

Answer Explanation

18 / 18 steps visible
01 · Step 1

Henry’s clue says that Wally is one of Vicky’s exactly 2 criminal neighbors. That directly identifies Wally as a criminal. So Wally must be criminal.

02 · Step 2

Wally’s clue says there are exactly 3 innocents below Donna. Below Donna, there is already 1 known innocent, and the only unknown people left there are Nick and Stella. That means the 2 remaining innocent spots below Donna have to be Nick and Stella. So Nick and Stella must be innocent.

03 · Step 3

Henry’s clue says that Wally is one of Vicky’s exactly 2 criminal neighbors. Among Vicky’s neighbors, Stella is already innocent and Wally is already one criminal, so the only still-unknown neighbor left in that group is Rob. That means Rob has to be the second criminal neighbor Vicky has. So Rob must be criminal.

04 · Step 4

Nick’s clue says Stella has exactly 3 innocent neighbors, and exactly 2 of those innocent neighbors also neighbor Joy. In the overlap between Stella’s neighbors and Joy’s neighbors, the only people are Nick, who is already innocent, and Ollie. That overlap still needs 1 more innocent person, and Ollie is the only unknown person left there. So Ollie must be innocent.

05 · Step 5

Stella's neighbors must contain exactly 3 innocents in total, and 2 of those are already Nick and Ollie, so among Stella's four still-unknown neighbors there is room for exactly 1 more innocent. In that unknown group, the only people who can still be that innocent are Lisa, Tina, or Vicky. That means Xavi cannot be the innocent one in that group. So Xavi must be criminal.

06 · Step 6

Above Zoe, all criminals have to form one connected block. The three people strictly between Freya and Zoe are Kyle, Paul, and Uma, and that group contains exactly two criminals. With exactly two criminals among Kyle, Paul, and Uma, the only connected criminal blocks that fit are Kyle and Paul, Freya and Kyle and Paul, or Paul and Uma. In every one of those working blocks, Paul is included. So Paul must be criminal.

07 · Step 7

Paul's clue says Eve has exactly 4 innocent neighbors, and exactly 2 of those innocent neighbors are above Stella. Among Eve's neighbors who are above Stella, Henry is already known to be innocent, and the only other person there is Donna. That means the above-Stella group still needs 1 more innocent, so Donna must be innocent.

08 · Step 8

Eve’s neighbors must contain exactly 4 innocents, and Donna and Henry are already known innocents there, so among the three still-unknown neighbors of Eve, exactly 1 is criminal. In that unknown trio, the only people who can still be that criminal are Joy and Kyle. So Freya cannot be the criminal one in that group. That makes Freya innocent.

09 · Step 9

Eve’s clue says her neighbors contain exactly 4 innocents, and exactly 2 of those innocents are above Stella. Those 2 are already Donna and Henry, so among Eve’s other neighboring unknowns, Joy and Kyle, exactly one must be innocent. Donna’s clue says row 2 has an odd number of innocents, and row 2 already has Henry as 1 known innocent. Since Joy and Kyle contribute exactly one more innocent in that row, Gabe must be the additional innocent that makes the row’s total odd. So Gabe must be innocent.

10 · Step 10

Paul’s clue makes Eve’s neighbors contain exactly one criminal, and that one criminal is among Joy and Kyle. So within Freya’s neighbors, the pair Joy and Kyle already accounts for exactly one criminal, which is an odd number. Freya’s clue says her neighbors must contain an odd number of criminals. Since Joy and Kyle already provide that odd count, the only other neighbor, Eve, cannot also be a criminal without making the total even. So Eve must be innocent.

11 · Step 11

Stella’s neighbors must contain exactly 3 innocents in total, and 2 of those are already known to be Nick and Ollie, so among Stella’s still-unknown neighbors A3 Lisa, C4 Tina, and A5 Vicky there is exactly 1 innocent. In that three-person group, the only ones who can still be that innocent are Tina and Vicky. So Lisa cannot be the innocent one there. That makes Lisa criminal.

12 · Step 12

Lisa's clue says rows 1 and 2 have the same number of criminals. Row 1 currently has no known criminals, and the only unresolved person left in that row is Betty. From Paul's clue, Eve's neighbors contain exactly 1 criminal among Joy and Kyle, so row 2 gains exactly 1 criminal. Therefore row 1 must also gain exactly 1 criminal, and since Betty is the only open spot there, Betty must be criminal.

13 · Step 13

Betty’s clue says column A has exactly one innocent. In column A, Gabe is already that one known innocent, and Vicky is the only unknown person left there. So Vicky cannot be innocent. That makes Vicky criminal.

14 · Step 14

Nick’s clue says Stella has exactly 3 innocent neighbors, and exactly 2 of those innocent neighbors also neighbor Joy. Those 2 are already identified as Nick and Ollie. So Stella’s neighbors still need exactly 1 more innocent who is not a neighbor of Joy. Among Stella’s neighbors who are not neighbors of Joy, everyone is already a criminal except Tina, so Tina must be innocent.

15 · Step 15

Ollie says only one row has exactly 3 criminals. Row 5 already has Vicky, Wally, and Xavi as criminals, so if Zoe were also a criminal then row 5 would have 4 criminals instead of exactly 3. That means the row with exactly 3 criminals must be some other row, so Zoe cannot be a criminal. So Zoe must be innocent.

16 · Step 16

Between Freya and Zoe, there must be exactly one innocent, and among the people there, the only unknowns are Kyle and Uma. Paul's neighbors must contain an odd number of criminals, and among those neighbors, the only unknowns are Joy, Kyle, and Uma. If Joy were criminal, then Kyle and Uma would be the same two people who must both finish the Freya-to-Zoe count and the criminal-neighbor count for Paul at the same time, but they cannot satisfy both of those requirements together. So Joy cannot be criminal. That makes Joy innocent.

17 · Step 17

Paul’s clue fixes Eve’s neighboring group at exactly 4 innocents in total. It also says exactly 2 of those innocents are above Stella, and those 2 are already Donna and Henry. That leaves the neighbors not above Stella as Freya, Joy, and Kyle, and Freya and Joy already account for the 2 innocents allowed in that remainder. So Kyle must be criminal.

18 · Step 18

Xavi’s clue says there is exactly one innocent between Freya and Zoe. Among the people strictly between them, there are currently no known innocents, and the only unknown person left there is Uma. So Uma must be innocent.

Just the answer

Answer (spoilers)

Criminal · 8
Betty, Kyle, Lisa, Paul, Rob, Vicky, Wally, Xavi
Innocent · 12
Donna, Eve, Freya, Gabe, Henry, Joy, Nick, Ollie, Stella, Tina, Uma, Zoe

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