Puzzle Pack #2 Puzzle 41 Answer

Scott’s clue says there are exactly 2 innocent people who are neighbors of both Ruth and Vince. The shared group is just Pam and Wanda. Since those 2 innocent spots in the shared group still have to be filled, and Pam and Wanda are the only people there, Pam and Wanda must both be innocent.

Pam’s clue means row 1 has at least 3 criminals. Wanda’s clue says the coders and the painters must have the same number of innocents, but right now the coders already have 1 known innocent, Scott, while the painters have 0 known innocents. If Evie, Olive, and Zoe were all innocent, then row 1 would need Anna, Clyde, and David to supply the needed criminals, while Olive and Zoe would raise the innocent coders total above the innocent painters total. That makes the two clue requirements conflict. So Evie, Olive, and Zoe must be criminal.

The people above Wanda are Clyde, Gary, Mary, and Ruth, and that group must contain an odd number of criminals. From Zoe's clue, the people directly above pilots are Clyde, Mary, and Ruth, and exactly 2 of those 3 are criminals. That means those three contribute an even number of criminals to the group above Wanda. Gary is the only person above Wanda who is not part of that exact-count group, so he has to be criminal to make the total above Wanda odd. So Gary must be criminal.

Pam’s clue says there are more criminals than innocents in row 1. In row 1, Evie is already a known criminal and nobody there is known innocent, so the only way for row 1 to have more criminals than innocents is for Anna not to be innocent. So Anna must be criminal.

Mary has exactly 4 innocent neighbors, and Pam and Scott are already known to be innocent neighbors of Mary. Anna says that only 1 of Mary’s 4 innocent neighbors is also Anna’s neighbor. Among the people who are both Mary’s neighbors and Anna’s neighbors, Gary is known criminal, so the only person there who could be that 1 innocent is Frank. So Frank must be innocent.

Frank’s clue says David has exactly 2 innocent neighbors, and only 1 of those 2 is also Gary’s neighbor. Among David’s unknown neighbors, Clyde and Hazel are the ones who are Gary’s neighbors, while Isaac is not. So the one innocent neighbor of David who is not Gary’s neighbor has to be Isaac. That makes Isaac innocent.

Mary’s clue says she has exactly 4 innocent neighbors, and exactly 1 of those innocents is Anna’s neighbor. Among Mary’s neighbors, Frank, Pam, and Scott are already known innocents, and Frank is the only one of those three who is Anna’s neighbor. So the other three innocent neighbors Mary needs are already accounted for as Frank, Pam, and Scott, which means none of Mary’s unknown neighbors can be innocent. That makes Ruth criminal.

Mary has exactly 4 innocent neighbors, and 3 of those innocents are already known: Frank, Pam, and Scott. Anna says only 1 of Mary’s 4 innocent neighbors is also Anna’s neighbor, and among those three known innocents, only Frank is Anna’s neighbor. So the remaining unknown neighbor of Mary cannot also be Anna’s neighbor, which rules out Hazel and Nick and leaves Jason as Mary’s fourth innocent neighbor. Olive’s neighbors must contain an odd number of innocents. Isaac and Scott are already innocent there, so the unknown neighbors of Olive must contribute an odd number of additional innocents. Since Jason is Mary’s remaining innocent neighbor, Tom cannot be the extra innocent needed for Mary’s clue, and with the edge total also limited to 6 innocents, Tom is not one of the edge innocents. So Tom and Jason must be criminals.

Tom’s clue says Frank and Zoe have the same number of innocent neighbors. Frank’s known neighbors currently include 3 known criminals, 0 known innocents, and 2 unknowns, while Zoe’s known neighbors include 1 known criminal, 1 known innocent, and 1 unknown, namely Xia. Since Zoe already has 1 known innocent neighbor and Frank has 0 known innocent neighbors so far, Zoe’s remaining unknown neighbor cannot also be innocent if their innocent-neighbor totals are to stay equal. So Xia must be criminal.

Isaac’s clue says there are exactly 6 innocents on the edges. The edge cells already contain 4 known innocents, so the 2 remaining edge innocents must come from the only 3 unknown edge people: Clyde, David, and Vince. Pam’s clue says there are more criminals than innocents in row 1, and row 1 already has Anna and Evie as criminals, so Clyde and David cannot both be innocent. That means the two remaining edge innocents cannot both be in row 1, so one of them has to be Vince. So Vince must be innocent.

Hazel’s clue says her neighbors contain exactly 3 innocents in total, and exactly 1 of those innocents is in row 1. Vince’s clue also says Frank’s neighbors and Isaac’s neighbors must have the same number of criminal neighbors, but Frank already has 3 known criminal neighbors while Isaac has only 2. If Hazel were innocent, then the remaining open people involved here, Clyde, David, Mary, and Nick, would have to make both of those clues true at the same time. That cannot be done. So Hazel must be criminal.

Evie’s clue says Olive has an odd number of innocent neighbors. Olive’s neighbors currently include 2 known innocents, and the only unknown neighbor left is Nick. Since 2 is even, Nick has to be innocent to make Olive’s total number of innocent neighbors odd. So Nick must be innocent.

Hazel’s neighbors must contain exactly 3 innocents in total, and exactly 1 of those innocents is in row 1. Among Hazel’s neighbors who are not in row 1, the people are Gary, Isaac, Mary, Nick, and Olive, and that group already contains 2 known innocents: Isaac and Nick. So any remaining unknown person there cannot also be innocent. That makes Mary criminal.

Zoe says that exactly 2 pilots have a criminal directly above them. The pilots are Gary, Ruth, and Wanda. Gary already has Clyde directly above him, Ruth already has Mary directly above her, and Wanda already has Ruth directly above her; since Mary and Ruth are criminals, Ruth and Wanda are the 2 pilots who satisfy Zoe's clue. That means Gary cannot also have a criminal directly above him, so Clyde must be innocent.

Pam’s clue says there are more criminals than innocents in row 1. Between Anna and Evie, the people are Clyde and David, and among those two, Clyde is already known innocent while David is the only unknown. For row 1 to have more criminals than innocents, David cannot be innocent alongside Clyde. So David must be criminal.