Puzzle Pack #2 Puzzle 35 Answer

Vince’s clue says there is exactly one innocent among the people who are neighbors of both Rose and Stella. That shared group is Larry, Mark, Vince, and Wanda, and Vince is already the one known innocent in it. So the other three people in that shared group cannot be innocent. That makes Larry, Mark, and Wanda criminals.

Wanda’s clue says that Isaac is one of Donna’s two innocent neighbors. That directly identifies Isaac as innocent. So Isaac must be innocent.

Donna’s neighbors are Claire, Hank, and Isaac, and Wanda’s clue says exactly 2 of those neighbors are innocent. Since Isaac is already innocent, Claire and Hank together contain exactly 1 innocent. Isaac says he has exactly 3 innocent neighbors, and among his neighbors the unknown people are Claire, Donna, Hank, and Oscar, with Mark already criminal. Claire and Hank account for only 1 innocent, so the remaining 2 innocent neighbors Isaac still needs must be Donna and Oscar. So Donna and Oscar must be innocent.

Oscar’s clue directly says that Katie is one of the exactly 2 criminals above Peter. Since the clue explicitly includes Katie among those criminals, Katie must be criminal.

Donna has exactly 2 innocent neighbors, and Isaac is already one of them. Since Donna’s other neighbors are Claire and Hank, exactly 1 of Claire and Hank must be innocent. Mark’s clue says column C has exactly 4 criminals, so column C has exactly 1 innocent in total. That one innocent is already accounted for by Claire or Hank, and the only other unknown person in column C outside that pair is Stella. So Stella must be criminal.

Freya’s neighbors and Oscar’s neighbors must contain the same number of innocents. Right now Freya’s neighbors have 0 known innocents, while Oscar’s neighbors already have 1 known innocent, Isaac. Among the people who are both in row 2 and Freya’s neighbors, the only person is Gus. Among the people who are both in row 2 and Oscar’s neighbors, Isaac is already the innocent one, with Hank still unknown. So to match Oscar’s side within row 2, Gus has to be the innocent in Freya’s neighboring group. That makes Gus innocent.

Oscar’s clue says Freya and Oscar have the same number of innocent neighbors. Freya’s neighbors currently have 1 known innocent and 2 unknowns, while Oscar’s neighbors also have 1 known innocent and 1 unknown besides Tina. Since these two neighbor groups must end up with equal innocent counts, Tina cannot be an innocent neighbor for Oscar here. So Tina must be criminal.

Tina’s clue says that Uma is one of the exactly 3 innocents in the corner cells. That directly identifies Uma as innocent.

Above Peter, the three people are Andre, Freya, and Katie, and Oscar's clue says exactly 2 of them are criminals, with Katie being one of those criminals. In column A, Uma's clue says there is an odd number of innocents, and column A currently has 1 known innocent, with Andre, Freya, and Peter still unknown. If Peter were criminal, then only Andre and Freya would be left to satisfy both clues at once. But Andre and Freya would then have to make the group above Peter contain exactly 2 criminals while also making the total number of innocents in column A odd, and those requirements conflict. So Peter cannot be criminal. That makes Peter innocent.

Uma’s neighbors already have 2 known innocents, Peter and Vince. Donna’s clue says Bobby has more innocent neighbors than Uma, so Bobby’s neighbors must reach more than 2 innocents. At the same time, Donna’s own clue fixes her neighbors at exactly 2 innocents with Isaac as one of them, and Peter’s clue fixes the people above Peter at exactly 2 criminals with Katie as one of them. The same unknown people involved in those clues are Andre, Freya, Claire, and Hank, and if Rose were innocent they would have to satisfy all of those requirements together, but they cannot. So Rose must be criminal.

Wanda’s clue says Donna has exactly 2 innocent neighbors, and Isaac is one of them. Among Donna’s neighbors, Isaac is already the only known innocent, while the other two neighbors are Claire and Hank. So exactly one of Claire and Hank is innocent. That makes Hank innocent and Claire criminal.

Freya and Oscar must have the same number of innocent neighbors. Oscar already has 2 innocent neighbors, while Freya’s neighbor list currently has only 1 known innocent, so among Andre and Bobby there has to be exactly 1 more innocent to make Freya’s total also 2. Gus must have an odd number of innocent neighbors. He currently has 1 known innocent neighbor, and the unknown neighbors affecting that count are Andre, Bobby, and Freya. If Freya were criminal, then only Andre and Bobby could add innocents to these clues. But Andre and Bobby would need to contribute exactly 1 innocent for Freya’s count to match Oscar’s, and adding exactly 1 to Gus’s current total of 1 would make Gus’s innocent-neighbor count 2, which is even, not odd. So Freya at A2 must be innocent.

Oscar’s clue says Katie is one of exactly 2 criminals above Peter. The people above Peter are Andre, Freya, and Katie, and among them Katie is already a criminal while Freya is innocent. That leaves Andre as the only remaining person above Peter who can supply the second criminal. So Andre must be criminal.

Tina’s clue says Uma is one of exactly 3 innocents in the corner cells. In the corners, Donna and Uma are already known innocents, Andre is already a criminal, and Zoe is the only corner person still unknown. That means the third innocent corner has to be Zoe. So Zoe must be innocent.

Stella’s clue says Freya’s neighbors and Oscar’s neighbors must contain the same number of innocents. Right now Freya’s neighbors have 1 known innocent, while Oscar’s neighbors have 2, and the only unknown person involved here is Bobby among Freya’s neighbors. So Bobby has to supply that missing innocent for Freya’s neighbor count to match Oscar’s. That makes Bobby innocent.