Puzzle Pack #2 Puzzle 34 Answer

Vicky’s clue says Wanda has exactly 4 innocent neighbors, and exactly 2 of those innocent neighbors are below Donna. The only Wanda-neighbors who are below Donna are Tina and Xavi. Since those below-Donna spots still need 2 innocent people, Tina and Xavi must fill them both. So Tina and Xavi must be innocent.

Among Wanda's neighbors, Tina, Vicky, and Xavi are already innocent, and Wanda's clue says Wanda has exactly 4 innocent neighbors with exactly 2 of them below Donna. Since Tina and Xavi are the 2 innocent neighbors below Donna, the fourth innocent neighbor must come from A4 Phil or B4 Salil, so exactly 1 of Phil and Salil is innocent. Vicky's neighbors are Phil, Salil, and Wanda, and Tina's clue says that group contains an odd number of innocents. Phil and Salil already contribute exactly 1 innocent there, which is odd, so Wanda cannot also be innocent. So Wanda must be criminal.

Wanda’s clue says the people above Vicky contain exactly one innocent, so among Adam, Freya, Kevin, and Phil there is one innocent in total. From the current board and these clues, the only ones in that group who can still be that innocent are Freya, Kevin, or Phil. That means Adam cannot be the innocent one there. So Adam must be criminal.

Wanda’s unknown neighbors are Phil and Salil, and exactly 1 of those 2 is innocent. That means row 4 already has Tina as one innocent, plus exactly 1 more innocent among Phil and Salil, for a total of exactly 2 innocents in row 4. Uma is the only other unknown person in row 4 outside that Phil-or-Salil pair, so there is no innocent place left for her in that row. So Uma must be criminal.

Uma’s clue means that below Freya there are exactly 2 innocents, and Vicky is already one of them, so among Kevin and Phil there is exactly 1 innocent. Wanda’s clue says there is exactly 1 innocent above Vicky, and that group is Adam, Freya, Kevin, and Phil. Since Kevin and Phil already account for the only innocent allowed above Vicky, the only other unknown person there, Freya, cannot be innocent. So Freya must be criminal.

Row 4 and row 5 must have the same number of innocents. Right now row 4 has 1 known innocent, while row 5 already has 2 known innocents. The only unknowns these clues can still affect are Phil, Salil, and Zoe, so to bring the two rows into equality, row 5 cannot gain another innocent. That makes Zoe criminal.

Wanda’s unknown neighbors, Phil and Salil, contain exactly 1 innocent. Kevin and Linda’s shared neighbors contain exactly 2 innocents, and that shared group is Freya, Gary, Phil, and Salil. Since Freya is criminal and Phil plus Salil contribute only 1 innocent altogether, the second innocent in Kevin and Linda’s shared group has to be Gary. So Gary must be innocent.

Wanda’s clue says her neighbors contain exactly 4 innocents, and exactly 2 of those innocents are below Donna. Those 2 are already Tina and Xavi, so the other 2 innocent neighbors of Wanda must come from Phil, Salil, and Vicky, with Vicky already one of them. Gary’s clue says each person between Adam and Phil, namely Freya and Kevin, can have at most 2 innocent neighbors. Freya already has 1 known innocent neighbor, Gary, and Kevin also already has 1 known innocent neighbor, Gary. If Linda were innocent, then Carl, Kevin, Phil, and Salil would have to satisfy both clues at once, but that cannot be done without breaking those limits on Freya or Kevin’s innocent neighbors. So Linda cannot be innocent. That makes Linda criminal.

Linda’s clue says there are exactly 6 innocents on the edges, and exactly 2 of those edge innocents are neighbors of Gary. On the edge, the only known innocents so far are Vicky and Xavi, and both of them are not neighbors of Gary, so the 2 required innocent neighbors of Gary must come from the unknown edge neighbors of Gary: Carl, Donna, and Kevin. That makes Donna innocent.

Donna’s clue says that among Nancy’s neighbors, exactly 1 innocent is to the right of Kevin. In that right-of-Kevin group, Linda is already known to be criminal, so that group still needs 1 innocent. The only unknown person left there is Ollie. So Ollie must be innocent.

Linda’s clue fixes the edge innocents: there are 6 innocents on the edges in total, and exactly 2 of them are Gary’s neighbors, so the edge people who are not Gary’s neighbors must contain exactly 4 innocents. In that non-neighbor group, Ollie, Vicky, and Xavi are already known innocents, so there is room for exactly 1 more innocent among D1 Ellie, D2 Isaac, and A4 Phil. That one innocent must come from Ellie or Phil, so Isaac cannot be innocent. So Isaac must be criminal.

Linda’s clue says she has exactly 4 innocent neighbors. Among Linda’s neighbors, 2 are already known to be innocent, so the still-unknown neighbors must contain exactly 2 innocents. In that still-unknown group, the only people who can still be innocent are Helen, Kevin, Phil, and Salil. Nancy is not one of the possible innocent spots there, so she cannot be innocent. So Nancy must be criminal.

Donna’s clue says her neighbors contain an odd number of criminals. Right now that group already has 1 known criminal, and the unknown neighbors are Carl, Ellie, and Helen. If Helen were innocent, then Carl and Ellie would have to fit that odd-criminal requirement while also matching Wanda’s clue that exactly 1 person above Vicky is innocent and Linda’s clue that the edge has exactly 6 innocents, with exactly 2 of those innocents neighboring Gary. But with the same unsettled people Carl, Ellie, Kevin, and Phil also needing to satisfy those two edge and above-Vicky counts, Helen being innocent makes those clue requirements clash. So Helen must be criminal.

Wanda’s clue fixes her neighbors at exactly 4 innocents in total, and among Wanda’s still-unknown neighbors, exactly 1 is innocent: Phil or Salil. Linda’s clue says Linda has exactly 4 innocent neighbors, and in Linda’s neighbor list the only unknowns are Kevin, Phil, and Salil. Since Phil and Salil together contribute only 1 innocent, the remaining innocent needed for Linda’s total has to come from the only other unknown there, Kevin. So Kevin must be innocent.

Donna’s clue says Nancy’s neighbors contain exactly 4 innocents in total, and exactly 1 of those innocents is to the right of Kevin. That means the other 3 innocent neighbors of Nancy must be not to the right of Kevin. Among Nancy’s neighbors who are not to the right of Kevin, Gary and Tina are already known innocents, so that group still needs 1 more innocent. The only unknown person left in that group is Salil, so Salil must be innocent.

Vicky's clue says Wanda's neighbors contain exactly 4 innocents in total, and exactly 2 of those innocents are below Donna. Those 2 are already Tina and Xavi. Among Wanda's neighbors who are not below Donna, Salil and Vicky are already innocent, so that non-below group already contains the other 2 innocents allowed by the clue. Phil is the only unknown left there, so Phil cannot be innocent. So Phil must be criminal.

Gary’s clue applies to the people strictly between Adam and Phil, which are Freya and Kevin, and says each of them can have at most 2 innocent neighbors. Freya already has 2 known innocent neighbors, and Carl is one of Freya’s unknown neighbors. Kevin also already has 2 known innocent neighbors. If Carl were innocent, then Freya would have more than 2 innocent neighbors, which would break the clue. So Carl cannot be innocent. That makes Carl criminal.

Linda’s clue says there are exactly 6 innocents on the edge, and exactly 2 of those edge innocents are neighbors of Gary. That means the edge people who are not neighbors of Gary must contain exactly 4 innocents. In that non-neighbor edge group, D3 Ollie, A5 Vicky, and C5 Xavi are already known innocents, so that group still needs 1 more innocent. The only unknown person left in that group is D1 Ellie, so Ellie must be innocent.