Puzzle Pack #2 Puzzle 32 Answer

Zoe is at D5, so the people above her are D1, D2, D3, and D4. Peter is at C4, and the people who neighbor Peter are B3, C3, D3, B4, D4, B5, C5, and D5. The people who are both above Zoe and neighbors of Peter are only D3 and D4. Alice says there are no innocents in that group, so neither D3 nor D4 can be innocent. Therefore, we can determine that D3 is CRIMINAL and D4 is CRIMINAL.

Row 1 contains A1, B1, C1, and D1, and the clue says there are exactly two criminals there and that those two are connected. Since A1 is already known to be innocent, the two criminals in row 1 cannot be separated at B1 and D1, because then they would not form one continuous horizontal group. That means the criminal pair in row 1 must include C1, either as B1 and C1 or as C1 and D1. Therefore, we can determine that C1 is CRIMINAL.

Carl is at C1, and his edge neighbors are B1, B2, C2, and D2. Since Alice at A1 is innocent and Maria at D3 and Rose at D4 are irrelevant to Carl’s neighboring edge count, the clue from Carl tells us that among B1, B2, C2, and D2, an odd number are innocent. Rose says both criminals in row 1 are connected. Row 1 already has Carl at C1 as a criminal and Alice at A1 as innocent, so the only way to have both row 1 criminals connected is for B1 to be the other criminal and D1 not to be a criminal. That fixes B1 as criminal, leaving B2, C2, and D2 as the only edge neighbors of Carl that could be innocent. Carl needs an odd number of innocent edge neighbors, and with B1 already criminal, that means an odd number among B2, C2, and D2 must be innocent. In this round, that forces D2 to be the criminal among the unresolved options. Therefore, we can determine that D2 is CRIMINAL.

Hilda is at C2, so her row 3 neighbors are B3, C3, and D3. Isaac says Hilda has exactly 3 innocent neighbors in total, and exactly 2 of those 3 are in row 3. Since D3 is Maria and she is already known to be a criminal, the only row 3 neighbors of Hilda who can be the 2 innocents in row 3 are B3 and C3. Therefore, we can determine that B3 is INNOCENT and C3 is INNOCENT.